Find the Maximum/Minimum Value f(x)=3x^2-6x-1

$f (x) = 3 x^{2} - 6 x - 1$

The minimum of a quadratic function occurs at $x = - \frac{b}{2 a}$ . If $a$ is positive, the minimum value of the function is $f (- \frac{b}{2 a})$ .

$f_{min}$ $x = a x^{2} + b x + c$ occurs at $x = - \frac{b}{2 a}$

Find the value of $x = - \frac{b}{2 a}$ .

Substitute in the values of $a$ and $b$ .

$x = - \frac{- 6}{2 (3)}$

Remove parentheses.

$x = - \frac{- 6}{2 (3)}$

Simplify $- \frac{- 6}{2 (3)}$ .

Cancel the common factor of $- 6$ and $2$ .

Factor $2$ out of $- 6$ .

$x = - \frac{2 \cdot - 3}{2 \cdot 3}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 3$ .

$x = - \frac{2 \cdot - 3}{2 (3)}$

Cancel the common factor.

$x = - \frac{2 \cdot - 3}{2 \cdot 3}$

Rewrite the expression.

$x = - \frac{- 3}{3}$

Cancel the common factor of $- 3$ and $3$ .

Factor $3$ out of $- 3$ .

$x = - \frac{3 \cdot - 1}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$x = - \frac{3 \cdot - 1}{3 (1)}$

Cancel the common factor.

$x = - \frac{3 \cdot - 1}{3 \cdot 1}$

Rewrite the expression.

$x = - \frac{- 1}{1}$

Divide $- 1$ by $1$ .

$x = - - 1$

Multiply $- 1$ by $- 1$ .

$x = 1$

Evaluate $f (1)$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = 3 {(1)}^{2} - 6 \cdot 1 - 1$

Simplify the result.

Simplify each term.

One to any power is one.

$f (1) = 3 \cdot 1 - 6 \cdot 1 - 1$

Multiply $3$ by $1$ .

$f (1) = 3 - 6 \cdot 1 - 1$

Multiply $- 6$ by $1$ .

$f (1) = 3 - 6 - 1$

Simplify by subtracting numbers.

Subtract $6$ from $3$ .

$f (1) = - 3 - 1$

Subtract $1$ from $- 3$ .

$f (1) = - 4$

The final answer is $- 4$ .

$- 4$

Use the $x$ and $y$ values to find where the minimum occurs.

$(1, - 4)$

Find the Maximum/Minimum Value f(x)=3x^2-6x-1

Related Questions

Support LCMGCF.com by disabling your adblocker.