Find the Maximum/Minimum Value (x+1)(x-2)(x-3)

$(x + 1) (x - 2) (x - 3)$

Step 1

Find the first derivative of the function.

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = (x + 1) (x - 2)$ and $g (x) = x - 3$ .

$(x + 1) (x - 2) \frac{d}{d x} [x - 3] + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Differentiate.

By the Sum Rule, the derivative of $x - 3$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 3]$ .

$(x + 1) (x - 2) (\frac{d}{d x} [x] + \frac{d}{d x} [- 3]) + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$(x + 1) (x - 2) (1 + \frac{d}{d x} [- 3]) + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$(x + 1) (x - 2) (1 + 0) + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Simplify the expression.

Add $1$ and $0$ .

$(x + 1) (x - 2) \cdot 1 + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Multiply $x + 1$ by $1$ .

$(x + 1) (x - 2) + (x - 3) \frac{d}{d x} [(x + 1) (x - 2)]$

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x + 1$ and $g (x) = x - 2$ .

$(x + 1) (x - 2) + (x - 3) ((x + 1) \frac{d}{d x} [x - 2] + (x - 2) \frac{d}{d x} [x + 1])$

Differentiate.

By the Sum Rule, the derivative of $x - 2$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 2]$ .

$(x + 1) (x - 2) + (x - 3) ((x + 1) (\frac{d}{d x} [x] + \frac{d}{d x} [- 2]) + (x - 2) \frac{d}{d x} [x + 1])$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$(x + 1) (x - 2) + (x - 3) ((x + 1) (1 + \frac{d}{d x} [- 2]) + (x - 2) \frac{d}{d x} [x + 1])$

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2$ with respect to $x$ is $0$ .

$(x + 1) (x - 2) + (x - 3) ((x + 1) (1 + 0) + (x - 2) \frac{d}{d x} [x + 1])$

Simplify the expression.

Add $1$ and $0$ .

$(x + 1) (x - 2) + (x - 3) ((x + 1) \cdot 1 + (x - 2) \frac{d}{d x} [x + 1])$

Multiply $x + 1$ by $1$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) \frac{d}{d x} [x + 1])$

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (\frac{d}{d x} [x] + \frac{d}{d x} [1]))$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (1 + \frac{d}{d x} [1]))$

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (1 + 0))$

Simplify by adding terms.

Add $1$ and $0$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) \cdot 1)$

Multiply $x - 2$ by $1$ .

$(x + 1) (x - 2) + (x - 3) (x + 1 + x - 2)$

Add $x$ and $x$ .

$(x + 1) (x - 2) + (x - 3) (2 x + 1 - 2)$

Subtract $2$ from $1$ .

$(x + 1) (x - 2) + (x - 3) (2 x - 1)$

Simplify.

Apply the distributive property.

$(x + 1) x + (x + 1) \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$x \cdot x + 1 x + (x + 1) \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + (x - 3) (2 x) + (x - 3) \cdot - 1$

Apply the distributive property.

$x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + (x - 3) \cdot - 1$

Apply the distributive property.

$x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Combine terms.

Raise $x$ to the power of $1$ .

$x^{1} x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$x^{1} x^{1} + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{1 + 1} + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Add $1$ and $1$ .

$x^{2} + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $x$ by $1$ .

$x^{2} + x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Move $- 2$ to the left of $x$ .

$x^{2} + x - 2 \cdot x + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $- 2$ by $1$ .

$x^{2} + x - 2 x - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Subtract $2 x$ from $x$ .

$x^{2} - x - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$x^{2} - x - 2 + 2 (x^{1} x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$x^{2} - x - 2 + 2 (x^{1} x^{1}) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{2} - x - 2 + 2 x^{1 + 1} - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Add $1$ and $1$ .

$x^{2} - x - 2 + 2 x^{2} - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $2$ by $- 3$ .

$x^{2} - x - 2 + 2 x^{2} - 6 x + x \cdot - 1 - 3 \cdot - 1$

Move $- 1$ to the left of $x$ .

$x^{2} - x - 2 + 2 x^{2} - 6 x - 1 \cdot x - 3 \cdot - 1$

Rewrite $- 1 x$ as $- x$ .

$x^{2} - x - 2 + 2 x^{2} - 6 x - x - 3 \cdot - 1$

Multiply $- 3$ by $- 1$ .

$x^{2} - x - 2 + 2 x^{2} - 6 x - x + 3$

Subtract $x$ from $- 6 x$ .

$x^{2} - x - 2 + 2 x^{2} - 7 x + 3$

Add $x^{2}$ and $2 x^{2}$ .

$3 x^{2} - x - 2 - 7 x + 3$

Subtract $7 x$ from $- x$ .

$3 x^{2} - 8 x - 2 + 3$

Add $- 2$ and $3$ .

$3 x^{2} - 8 x + 1$

Step 2

Find the second derivative of the function.

By the Sum Rule, the derivative of $3 x^{2} - 8 x + 1$ with respect to $x$ is $\frac{d}{d x} [3 x^{2}] + \frac{d}{d x} [- 8 x] + \frac{d}{d x} [1]$ .

$f'' (x) = \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (- 8 x) + \frac{d}{d x} (1)$

Evaluate $\frac{d}{d x} [3 x^{2}]$ .

Since $3$ is constant with respect to $x$ , the derivative of $3 x^{2}$ with respect to $x$ is $3 \frac{d}{d x} [x^{2}]$ .

$f'' (x) = 3 \frac{d}{d x} (x^{2}) + \frac{d}{d x} (- 8 x) + \frac{d}{d x} (1)$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f'' (x) = 3 (2 x) + \frac{d}{d x} (- 8 x) + \frac{d}{d x} (1)$

Multiply $2$ by $3$ .

$f'' (x) = 6 x + \frac{d}{d x} (- 8 x) + \frac{d}{d x} (1)$

Evaluate $\frac{d}{d x} [- 8 x]$ .

Since $- 8$ is constant with respect to $x$ , the derivative of $- 8 x$ with respect to $x$ is $- 8 \frac{d}{d x} [x]$ .

$f'' (x) = 6 x - 8 \frac{d}{d x} x + \frac{d}{d x} (1)$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = 6 x - 8 \cdot 1 + \frac{d}{d x} (1)$

Multiply $- 8$ by $1$ .

$f'' (x) = 6 x - 8 + \frac{d}{d x} (1)$

Differentiate using the Constant Rule.

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$f'' (x) = 6 x - 8 + 0$

Add $6 x - 8$ and $0$ .

$f'' (x) = 6 x - 8$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$3 x^{2} - 8 x + 1 = 0$

Step 4

Find the first derivative.

$f' (x) = (x + 1) (x - 2) \frac{d}{d x} (x - 3) + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Differentiate.

By the Sum Rule, the derivative of $x - 3$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 3]$ .

$f' (x) = (x + 1) (x - 2) (\frac{d}{d x} (x) + \frac{d}{d x} (- 3)) + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f' (x) = (x + 1) (x - 2) (1 + \frac{d}{d x} (- 3)) + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$f' (x) = (x + 1) (x - 2) (1 + 0) + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Simplify the expression.

Add $1$ and $0$ .

$f' (x) = (x + 1) (x - 2) \cdot 1 + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Multiply $x + 1$ by $1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) \frac{d}{d x} ((x + 1) (x - 2))$

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x + 1$ and $g (x) = x - 2$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) ((x + 1) \frac{d}{d x} (x - 2) + (x - 2) \frac{d}{d x} (x + 1))$

Differentiate.

By the Sum Rule, the derivative of $x - 2$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [- 2]$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) ((x + 1) (\frac{d}{d x} (x) + \frac{d}{d x} (- 2)) + (x - 2) \frac{d}{d x} (x + 1))$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) ((x + 1) (1 + \frac{d}{d x} (- 2)) + (x - 2) \frac{d}{d x} (x + 1))$

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2$ with respect to $x$ is $0$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) ((x + 1) (1 + 0) + (x - 2) \frac{d}{d x} (x + 1))$

Simplify the expression.

Add $1$ and $0$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) ((x + 1) \cdot 1 + (x - 2) \frac{d}{d x} (x + 1))$

Multiply $x + 1$ by $1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) \frac{d}{d x} (x + 1))$

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (\frac{d}{d x} (x) + \frac{d}{d x} (1)))$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (1 + \frac{d}{d x} (1)))$

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) (1 + 0))$

Simplify by adding terms.

Add $1$ and $0$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + (x - 2) \cdot 1)$

Multiply $x - 2$ by $1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (x + 1 + x - 2)$

Add $x$ and $x$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (2 x + 1 - 2)$

Subtract $2$ from $1$ .

$f' (x) = (x + 1) (x - 2) + (x - 3) (2 x - 1)$

Simplify.

Apply the distributive property.

$f' (x) = (x + 1) x + (x + 1) \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$f' (x) = x \cdot x + 1 x + (x + 1) \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + (x - 3) (2 x - 1)$

Apply the distributive property.

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + (x - 3) (2 x) + (x - 3) \cdot - 1$

Apply the distributive property.

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + (x - 3) \cdot - 1$

Apply the distributive property.

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Combine terms.

Raise $x$ to the power of $1$ .

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$f' (x) = x \cdot x + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f' (x) = x^{1 + 1} + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Add $1$ and $1$ .

$f' (x) = x^{2} + 1 x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $x$ by $1$ .

$f' (x) = x^{2} + x + x \cdot - 2 + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Move $- 2$ to the left of $x$ .

$f' (x) = x^{2} + x - 2 \cdot x + 1 \cdot - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $- 2$ by $1$ .

$f' (x) = x^{2} + x - 2 x - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Subtract $2 x$ from $x$ .

$f' (x) = x^{2} - x - 2 + x (2 x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$f' (x) = x^{2} - x - 2 + 2 (x \cdot x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Raise $x$ to the power of $1$ .

$f' (x) = x^{2} - x - 2 + 2 (x \cdot x) - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f' (x) = x^{2} - x - 2 + 2 x^{1 + 1} - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Add $1$ and $1$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 3 (2 x) + x \cdot - 1 - 3 \cdot - 1$

Multiply $2$ by $- 3$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 6 x + x \cdot - 1 - 3 \cdot - 1$

Move $- 1$ to the left of $x$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 6 x - 1 \cdot x - 3 \cdot - 1$

Rewrite $- 1 x$ as $- x$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 6 x - x - 3 \cdot - 1$

Multiply $- 3$ by $- 1$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 6 x - x + 3$

Subtract $x$ from $- 6 x$ .

$f' (x) = x^{2} - x - 2 + 2 x^{2} - 7 x + 3$

Add $x^{2}$ and $2 x^{2}$ .

$f' (x) = 3 x^{2} - x - 2 - 7 x + 3$

Subtract $7 x$ from $- x$ .

$f' (x) = 3 x^{2} - 8 x - 2 + 3$

Add $- 2$ and $3$ .

$f' (x) = 3 x^{2} - 8 x + 1$

The first derivative of $f (x)$ with respect to $x$ is $3 x^{2} - 8 x + 1$ .

$3 x^{2} - 8 x + 1$

Step 5

Set the first derivative equal to $0$ then solve the equation $3 x^{2} - 8 x + 1 = 0$ .

Set the first derivative equal to $0$ .

$3 x^{2} - 8 x + 1 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 3$ , $b = - 8$ , and $c = 1$ into the quadratic formula and solve for $x$ .

$\frac{8 \pm \sqrt{{(- 8)}^{2} - 4 \cdot (3 \cdot 1)}}{2 \cdot 3}$

Simplify.

Simplify the numerator.

Raise $- 8$ to the power of $2$ .

$x = \frac{8 \pm \sqrt{64 - 4 \cdot 3 \cdot 1}}{2 \cdot 3}$

Multiply $- 4 \cdot 3 \cdot 1$ .

Multiply $- 4$ by $3$ .

$x = \frac{8 \pm \sqrt{64 - 12 \cdot 1}}{2 \cdot 3}$

Multiply $- 12$ by $1$ .

$x = \frac{8 \pm \sqrt{64 - 12}}{2 \cdot 3}$

Subtract $12$ from $64$ .

$x = \frac{8 \pm \sqrt{52}}{2 \cdot 3}$

Rewrite $52$ as $2^{2} \cdot 13$ .

Factor $4$ out of $52$ .

$x = \frac{8 \pm \sqrt{4 (13)}}{2 \cdot 3}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{8 \pm \sqrt{2^{2} \cdot 13}}{2 \cdot 3}$

Pull terms out from under the radical.

$x = \frac{8 \pm 2 \sqrt{13}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{8 \pm 2 \sqrt{13}}{6}$

Simplify $\frac{8 \pm 2 \sqrt{13}}{6}$ .

$x = \frac{4 \pm \sqrt{13}}{3}$

The final answer is the combination of both solutions.

$x = \frac{4 + \sqrt{13}}{3}, \frac{4 - \sqrt{13}}{3}$

Step 6

Find the values where the derivative is undefined.

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 7

Critical points to evaluate.

$x = \frac{4 + \sqrt{13}}{3}, \frac{4 - \sqrt{13}}{3}$

Step 8

Evaluate the second derivative at $x = \frac{4 + \sqrt{13}}{3}$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$6 (\frac{4 + \sqrt{13}}{3}) - 8$

Step 9

Evaluate the second derivative.

Simplify each term.

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$3 (2) \frac{4 + \sqrt{13}}{3} - 8$

Cancel the common factor.

$3 \cdot 2 \frac{4 + \sqrt{13}}{3} - 8$

Rewrite the expression.

$2 (4 + \sqrt{13}) - 8$

Apply the distributive property.

$2 \cdot 4 + 2 \sqrt{13} - 8$

Multiply $2$ by $4$ .

$8 + 2 \sqrt{13} - 8$

Simplify by subtracting numbers.

Subtract $8$ from $8$ .

$0 + 2 \sqrt{13}$

Add $0$ and $2 \sqrt{13}$ .

$2 \sqrt{13}$

Step 10

$x = \frac{4 + \sqrt{13}}{3}$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = \frac{4 + \sqrt{13}}{3}$ is a local minimum

Step 11

Find the y-value when $x = \frac{4 + \sqrt{13}}{3}$ .

Replace the variable $x$ with $\frac{4 + \sqrt{13}}{3}$ in the expression.

$f (\frac{4 + \sqrt{13}}{3}) = ((\frac{4 + \sqrt{13}}{3}) + 1) ((\frac{4 + \sqrt{13}}{3}) - 2) ((\frac{4 + \sqrt{13}}{3}) - 3)$

Simplify the result.

Write $1$ as a fraction with a common denominator.

$f (\frac{4 + \sqrt{13}}{3}) = (\frac{4 + \sqrt{13}}{3} + \frac{3}{3}) ((\frac{4 + \sqrt{13}}{3}) - 2) ((\frac{4 + \sqrt{13}}{3}) - 3)$

Combine the numerators over the common denominator.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{4 + \sqrt{13} + 3}{3} \cdot (((\frac{4 + \sqrt{13}}{3}) - 2) ((\frac{4 + \sqrt{13}}{3}) - 3))$

Add $4$ and $3$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot (((\frac{4 + \sqrt{13}}{3}) - 2) ((\frac{4 + \sqrt{13}}{3}) - 3))$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot ((\frac{4 + \sqrt{13}}{3} - 2 \cdot \frac{3}{3}) ((\frac{4 + \sqrt{13}}{3}) - 3))$

Combine fractions.

Combine $- 2$ and $\frac{3}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot ((\frac{4 + \sqrt{13}}{3} + \frac{- 2 \cdot 3}{3}) ((\frac{4 + \sqrt{13}}{3}) - 3))$

Combine the numerators over the common denominator.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot \frac{4 + \sqrt{13} - 2 \cdot 3}{3} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Simplify the numerator.

Multiply $- 2$ by $3$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot \frac{4 + \sqrt{13} - 6}{3} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Subtract $6$ from $4$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 + \sqrt{13}}{3} \cdot \frac{- 2 + \sqrt{13}}{3} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Multiply $\frac{7 + \sqrt{13}}{3} \cdot \frac{- 2 + \sqrt{13}}{3}$ .

Multiply $\frac{7 + \sqrt{13}}{3}$ by $\frac{- 2 + \sqrt{13}}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{(7 + \sqrt{13}) (- 2 + \sqrt{13})}{3 \cdot 3} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Multiply $3$ by $3$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{(7 + \sqrt{13}) (- 2 + \sqrt{13})}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Expand $(7 + \sqrt{13}) (- 2 + \sqrt{13})$ using the FOIL Method.

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 (- 2 + \sqrt{13}) + \sqrt{13} (- 2 + \sqrt{13})}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 \cdot - 2 + 7 \sqrt{13} + \sqrt{13} (- 2 + \sqrt{13})}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{7 \cdot - 2 + 7 \sqrt{13} + \sqrt{13} \cdot - 2 + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Simplify and combine like terms.

Simplify each term.

Multiply $7$ by $- 2$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} + \sqrt{13} \cdot - 2 + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Move $- 2$ to the left of $\sqrt{13}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} - 2 \cdot \sqrt{13} + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Combine using the product rule for radicals.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} - 2 \sqrt{13} + \sqrt{13 \cdot 13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Multiply $13$ by $13$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} - 2 \sqrt{13} + \sqrt{169}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Rewrite $169$ as $13^{2}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} - 2 \sqrt{13} + \sqrt{13^{2}}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Pull terms out from under the radical, assuming positive real numbers.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 14 + 7 \sqrt{13} - 2 \sqrt{13} + 13}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Add $- 14$ and $13$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 7 \sqrt{13} - 2 \sqrt{13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

Subtract $2 \sqrt{13}$ from $7 \sqrt{13}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot ((\frac{4 + \sqrt{13}}{3}) - 3)$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot (\frac{4 + \sqrt{13}}{3} - 3 \cdot \frac{3}{3})$

Combine fractions.

Combine $- 3$ and $\frac{3}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot (\frac{4 + \sqrt{13}}{3} + \frac{- 3 \cdot 3}{3})$

Combine the numerators over the common denominator.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot \frac{4 + \sqrt{13} - 3 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 3$ by $3$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot \frac{4 + \sqrt{13} - 9}{3}$

Subtract $9$ from $4$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 + 5 \sqrt{13}}{9} \cdot \frac{- 5 + \sqrt{13}}{3}$

Multiply $\frac{- 1 + 5 \sqrt{13}}{9} \cdot \frac{- 5 + \sqrt{13}}{3}$ .

Multiply $\frac{- 1 + 5 \sqrt{13}}{9}$ by $\frac{- 5 + \sqrt{13}}{3}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{(- 1 + 5 \sqrt{13}) (- 5 + \sqrt{13})}{9 \cdot 3}$

Multiply $9$ by $3$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{(- 1 + 5 \sqrt{13}) (- 5 + \sqrt{13})}{27}$

Expand $(- 1 + 5 \sqrt{13}) (- 5 + \sqrt{13})$ using the FOIL Method.

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 (- 5 + \sqrt{13}) + 5 \sqrt{13} (- 5 + \sqrt{13})}{27}$

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 \cdot - 5 - 1 \sqrt{13} + 5 \sqrt{13} (- 5 + \sqrt{13})}{27}$

Apply the distributive property.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{- 1 \cdot - 5 - 1 \sqrt{13} + 5 \sqrt{13} \cdot - 5 + 5 \sqrt{13} \sqrt{13}}{27}$

Simplify and combine like terms.

Simplify each term.

Multiply $- 1$ by $- 5$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - 1 \sqrt{13} + 5 \sqrt{13} \cdot - 5 + 5 \sqrt{13} \sqrt{13}}{27}$

Rewrite $- 1 \sqrt{13}$ as $- \sqrt{13}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} + 5 \sqrt{13} \cdot - 5 + 5 \sqrt{13} \sqrt{13}}{27}$

Multiply $- 5$ by $5$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \sqrt{13} \sqrt{13}}{27}$

Multiply $5 \sqrt{13} \sqrt{13}$ .

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 (\sqrt{13} \sqrt{13})}{27}$

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 (\sqrt{13} \sqrt{13})}{27}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 {\sqrt{13}}^{1 + 1}}{27}$

Add $1$ and $1$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 {\sqrt{13}}^{2}}{27}$

Rewrite ${\sqrt{13}}^{2}$ as $13$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{13}$ as $13^{\frac{1}{2}}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 {(13^{\frac{1}{2}})}^{2}}{27}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \cdot 13^{\frac{1}{2} \cdot 2}}{27}$

Combine $\frac{1}{2}$ and $2$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \cdot 13^{\frac{2}{2}}}{27}$

Cancel the common factor of $2$ .

Cancel the common factor.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \cdot 13^{\frac{2}{2}}}{27}$

Rewrite the expression.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \cdot 13}{27}$

Evaluate the exponent.

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 5 \cdot 13}{27}$

Multiply $5$ by $13$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{5 - \sqrt{13} - 25 \sqrt{13} + 65}{27}$

Add $5$ and $65$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{70 - \sqrt{13} - 25 \sqrt{13}}{27}$

Subtract $25 \sqrt{13}$ from $- \sqrt{13}$ .

$f (\frac{4 + \sqrt{13}}{3}) = \frac{70 - 26 \sqrt{13}}{27}$

The final answer is $\frac{70 - 26 \sqrt{13}}{27}$ .

$y = \frac{70 - 26 \sqrt{13}}{27}$

Step 12

Evaluate the second derivative at $x = \frac{4 - \sqrt{13}}{3}$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$6 (\frac{4 - \sqrt{13}}{3}) - 8$

Step 13

Evaluate the second derivative.

Simplify each term.

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$3 (2) \frac{4 - \sqrt{13}}{3} - 8$

Cancel the common factor.

$3 \cdot 2 \frac{4 - \sqrt{13}}{3} - 8$

Rewrite the expression.

$2 (4 - \sqrt{13}) - 8$

Apply the distributive property.

$2 \cdot 4 + 2 (- \sqrt{13}) - 8$

Multiply $2$ by $4$ .

$8 + 2 (- \sqrt{13}) - 8$

Multiply $- 1$ by $2$ .

$8 - 2 \sqrt{13} - 8$

Simplify by subtracting numbers.

Subtract $8$ from $8$ .

$0 - 2 \sqrt{13}$

Subtract $2 \sqrt{13}$ from $0$ .

$- 2 \sqrt{13}$

Step 14

$x = \frac{4 - \sqrt{13}}{3}$ is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.

$x = \frac{4 - \sqrt{13}}{3}$ is a local maximum

Step 15

Find the y-value when $x = \frac{4 - \sqrt{13}}{3}$ .

Replace the variable $x$ with $\frac{4 - \sqrt{13}}{3}$ in the expression.

$f (\frac{4 - \sqrt{13}}{3}) = ((\frac{4 - \sqrt{13}}{3}) + 1) ((\frac{4 - \sqrt{13}}{3}) - 2) ((\frac{4 - \sqrt{13}}{3}) - 3)$

Simplify the result.

Write $1$ as a fraction with a common denominator.

$f (\frac{4 - \sqrt{13}}{3}) = (\frac{4 - \sqrt{13}}{3} + \frac{3}{3}) ((\frac{4 - \sqrt{13}}{3}) - 2) ((\frac{4 - \sqrt{13}}{3}) - 3)$

Combine the numerators over the common denominator.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{4 - \sqrt{13} + 3}{3} \cdot (((\frac{4 - \sqrt{13}}{3}) - 2) ((\frac{4 - \sqrt{13}}{3}) - 3))$

Add $4$ and $3$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot (((\frac{4 - \sqrt{13}}{3}) - 2) ((\frac{4 - \sqrt{13}}{3}) - 3))$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot ((\frac{4 - \sqrt{13}}{3} - 2 \cdot \frac{3}{3}) ((\frac{4 - \sqrt{13}}{3}) - 3))$

Combine fractions.

Combine $- 2$ and $\frac{3}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot ((\frac{4 - \sqrt{13}}{3} + \frac{- 2 \cdot 3}{3}) ((\frac{4 - \sqrt{13}}{3}) - 3))$

Combine the numerators over the common denominator.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot \frac{4 - \sqrt{13} - 2 \cdot 3}{3} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Simplify the numerator.

Multiply $- 2$ by $3$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot \frac{4 - \sqrt{13} - 6}{3} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Subtract $6$ from $4$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 - \sqrt{13}}{3} \cdot \frac{- 2 - \sqrt{13}}{3} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $\frac{7 - \sqrt{13}}{3} \cdot \frac{- 2 - \sqrt{13}}{3}$ .

Multiply $\frac{7 - \sqrt{13}}{3}$ by $\frac{- 2 - \sqrt{13}}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{(7 - \sqrt{13}) (- 2 - \sqrt{13})}{3 \cdot 3} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $3$ by $3$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{(7 - \sqrt{13}) (- 2 - \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Expand $(7 - \sqrt{13}) (- 2 - \sqrt{13})$ using the FOIL Method.

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 (- 2 - \sqrt{13}) - \sqrt{13} (- 2 - \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 \cdot - 2 + 7 (- \sqrt{13}) - \sqrt{13} (- 2 - \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{7 \cdot - 2 + 7 (- \sqrt{13}) - \sqrt{13} \cdot - 2 - \sqrt{13} (- \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Simplify and combine like terms.

Simplify each term.

Multiply $7$ by $- 2$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 + 7 (- \sqrt{13}) - \sqrt{13} \cdot - 2 - \sqrt{13} (- \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $- 1$ by $7$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} - \sqrt{13} \cdot - 2 - \sqrt{13} (- \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $- 2$ by $- 1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} - \sqrt{13} (- \sqrt{13})}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $- \sqrt{13} (- \sqrt{13})$ .

Multiply $- 1$ by $- 1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 1 \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Multiply $\sqrt{13}$ by $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + \sqrt{13} \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + {\sqrt{13}}^{1 + 1}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Add $1$ and $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + {\sqrt{13}}^{2}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Rewrite ${\sqrt{13}}^{2}$ as $13$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{13}$ as $13^{\frac{1}{2}}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + {(13^{\frac{1}{2}})}^{2}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 13^{\frac{1}{2} \cdot 2}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Combine $\frac{1}{2}$ and $2$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 13^{\frac{2}{2}}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Cancel the common factor of $2$ .

Cancel the common factor.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 13^{\frac{2}{2}}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Rewrite the expression.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 13}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Evaluate the exponent.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 14 - 7 \sqrt{13} + 2 \sqrt{13} + 13}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Add $- 14$ and $13$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 7 \sqrt{13} + 2 \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

Add $- 7 \sqrt{13}$ and $2 \sqrt{13}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot ((\frac{4 - \sqrt{13}}{3}) - 3)$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot (\frac{4 - \sqrt{13}}{3} - 3 \cdot \frac{3}{3})$

Combine fractions.

Combine $- 3$ and $\frac{3}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot (\frac{4 - \sqrt{13}}{3} + \frac{- 3 \cdot 3}{3})$

Combine the numerators over the common denominator.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot \frac{4 - \sqrt{13} - 3 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 3$ by $3$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot \frac{4 - \sqrt{13} - 9}{3}$

Subtract $9$ from $4$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 - 5 \sqrt{13}}{9} \cdot \frac{- 5 - \sqrt{13}}{3}$

Multiply $\frac{- 1 - 5 \sqrt{13}}{9} \cdot \frac{- 5 - \sqrt{13}}{3}$ .

Multiply $\frac{- 1 - 5 \sqrt{13}}{9}$ by $\frac{- 5 - \sqrt{13}}{3}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{(- 1 - 5 \sqrt{13}) (- 5 - \sqrt{13})}{9 \cdot 3}$

Multiply $9$ by $3$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{(- 1 - 5 \sqrt{13}) (- 5 - \sqrt{13})}{27}$

Expand $(- 1 - 5 \sqrt{13}) (- 5 - \sqrt{13})$ using the FOIL Method.

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 (- 5 - \sqrt{13}) - 5 \sqrt{13} (- 5 - \sqrt{13})}{27}$

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 \cdot - 5 - 1 (- \sqrt{13}) - 5 \sqrt{13} (- 5 - \sqrt{13})}{27}$

Apply the distributive property.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{- 1 \cdot - 5 - 1 (- \sqrt{13}) - 5 \sqrt{13} \cdot - 5 - 5 \sqrt{13} (- \sqrt{13})}{27}$

Simplify and combine like terms.

Simplify each term.

Multiply $- 1$ by $- 5$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 - 1 (- \sqrt{13}) - 5 \sqrt{13} \cdot - 5 - 5 \sqrt{13} (- \sqrt{13})}{27}$

Multiply $- 1 (- \sqrt{13})$ .

Multiply $- 1$ by $- 1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + 1 \sqrt{13} - 5 \sqrt{13} \cdot - 5 - 5 \sqrt{13} (- \sqrt{13})}{27}$

Multiply $\sqrt{13}$ by $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} - 5 \sqrt{13} \cdot - 5 - 5 \sqrt{13} (- \sqrt{13})}{27}$

Multiply $- 5$ by $- 5$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} - 5 \sqrt{13} (- \sqrt{13})}{27}$

Multiply $- 5 \sqrt{13} (- \sqrt{13})$ .

Multiply $- 1$ by $- 5$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \sqrt{13} \sqrt{13}}{27}$

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 (\sqrt{13} \sqrt{13})}{27}$

Raise $\sqrt{13}$ to the power of $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 (\sqrt{13} \sqrt{13})}{27}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 {\sqrt{13}}^{1 + 1}}{27}$

Add $1$ and $1$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 {\sqrt{13}}^{2}}{27}$

Rewrite ${\sqrt{13}}^{2}$ as $13$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{13}$ as $13^{\frac{1}{2}}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 {(13^{\frac{1}{2}})}^{2}}{27}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \cdot 13^{\frac{1}{2} \cdot 2}}{27}$

Combine $\frac{1}{2}$ and $2$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \cdot 13^{\frac{2}{2}}}{27}$

Cancel the common factor of $2$ .

Cancel the common factor.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \cdot 13^{\frac{2}{2}}}{27}$

Rewrite the expression.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \cdot 13}{27}$

Evaluate the exponent.

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 5 \cdot 13}{27}$

Multiply $5$ by $13$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{5 + \sqrt{13} + 25 \sqrt{13} + 65}{27}$

Add $5$ and $65$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{70 + \sqrt{13} + 25 \sqrt{13}}{27}$

Add $\sqrt{13}$ and $25 \sqrt{13}$ .

$f (\frac{4 - \sqrt{13}}{3}) = \frac{70 + 26 \sqrt{13}}{27}$

The final answer is $\frac{70 + 26 \sqrt{13}}{27}$ .

$y = \frac{70 + 26 \sqrt{13}}{27}$

Step 16

These are the local extrema for $f (x) = (x + 1) (x - 2) (x - 3)$ .

$(\frac{4 + \sqrt{13}}{3}, \frac{70 - 26 \sqrt{13}}{27})$ is a local minima

$(\frac{4 - \sqrt{13}}{3}, \frac{70 + 26 \sqrt{13}}{27})$ is a local maxima

Step 17

Find the Maximum/Minimum Value (x+1)(x-2)(x-3)

Related Questions

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