Find the Mean 2 , 8 , 32 , 128

$2$ , $8$ , $32$ , $128$

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{2 + 8 + 32 + 128}{4}$

Cancel the common factor of $2 + 8 + 32 + 128$ and $4$ .

Factor $2$ out of $2$ .

$\frac{2 (1) + 8 + 32 + 128}{4}$

Factor $2$ out of $8$ .

$\frac{2 \cdot 1 + 2 \cdot 4 + 32 + 128}{4}$

Factor $2$ out of $2 \cdot 1 + 2 \cdot 4$ .

$\frac{2 \cdot (1 + 4) + 32 + 128}{4}$

Factor $2$ out of $32$ .

$\frac{2 \cdot (1 + 4) + 2 (16) + 128}{4}$

Factor $2$ out of $2 \cdot (1 + 4) + 2 (16)$ .

$\frac{2 \cdot (1 + 4 + 16) + 128}{4}$

Factor $2$ out of $128$ .

$\frac{2 \cdot (1 + 4 + 16) + 2 (64)}{4}$

Factor $2$ out of $2 \cdot (1 + 4 + 16) + 2 (64)$ .

$\frac{2 \cdot (1 + 4 + 16 + 64)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$\frac{2 \cdot (1 + 4 + 16 + 64)}{2 (2)}$

Cancel the common factor.

$\frac{2 \cdot (1 + 4 + 16 + 64)}{2 \cdot 2}$

Rewrite the expression.

$\frac{1 + 4 + 16 + 64}{2}$

Simplify the numerator.

Add $1$ and $4$ .

$\frac{5 + 16 + 64}{2}$

Add $5$ and $16$ .

$\frac{21 + 64}{2}$

Add $21$ and $64$ .

$\frac{85}{2}$

Divide.

$42.5$