Find the Mean 412 , 428 , 475 , 462 , 481 , 407 , 420 , 467 , 472 , 408

$412$ , $428$ , $475$ , $462$ , $481$ , $407$ , $420$ , $467$ , $472$ , $408$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{412 + 428 + 475 + 462 + 481 + 407 + 420 + 467 + 472 + 408}{10}$

Step 2

Simplify the numerator.

Add $412$ and $428$ .

$\frac{840 + 475 + 462 + 481 + 407 + 420 + 467 + 472 + 408}{10}$

Add $840$ and $475$ .

$\frac{1315 + 462 + 481 + 407 + 420 + 467 + 472 + 408}{10}$

Add $1315$ and $462$ .

$\frac{1777 + 481 + 407 + 420 + 467 + 472 + 408}{10}$

Add $1777$ and $481$ .

$\frac{2258 + 407 + 420 + 467 + 472 + 408}{10}$

Add $2258$ and $407$ .

$\frac{2665 + 420 + 467 + 472 + 408}{10}$

Add $2665$ and $420$ .

$\frac{3085 + 467 + 472 + 408}{10}$

Add $3085$ and $467$ .

$\frac{3552 + 472 + 408}{10}$

Add $3552$ and $472$ .

$\frac{4024 + 408}{10}$

Add $4024$ and $408$ .

$\frac{4432}{10}$

Step 3

Cancel the common factor of $4432$ and $10$ .

Factor $2$ out of $4432$ .

$\frac{2 (2216)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$\frac{2 \cdot 2216}{2 \cdot 5}$

Cancel the common factor.

$\frac{2 \cdot 2216}{2 \cdot 5}$

Rewrite the expression.

$\frac{2216}{5}$

Step 4

Divide.

$443.2$