Find the Midpoint ( square root of 8,2) , ( square root of 2,-2)

$(\sqrt{8}, 2)$ , $(\sqrt{2}, - 2)$

Step 1

Rewrite $8$ as $2^{2} \cdot 2$ .

Factor $4$ out of $8$ .

$(\sqrt{4 (2)}, 2) - (\sqrt{2}, - 2)$

Rewrite $4$ as $2^{2}$ .

$(\sqrt{2^{2} \cdot 2}, 2) - (\sqrt{2}, - 2)$

Step 2

Pull terms out from under the radical.

$(2 \sqrt{2}, 2) - (\sqrt{2}, - 2)$

Step 3

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 4

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{2 \sqrt{2} + \sqrt{2}}{2}, \frac{2 - 2}{2})$

Step 5

Add $2 \sqrt{2}$ and $\sqrt{2}$ .

$(\frac{3 \sqrt{2}}{2}, \frac{2 - 2}{2})$

Step 6

Cancel the common factor of $2 - 2$ and $2$ .

Factor $2$ out of $2$ .

$(\frac{3 \sqrt{2}}{2}, \frac{2 \cdot 1 - 2}{2})$

Factor $2$ out of $- 2$ .

$(\frac{3 \sqrt{2}}{2}, \frac{2 \cdot 1 + 2 \cdot - 1}{2})$

Factor $2$ out of $2 \cdot 1 + 2 \cdot - 1$ .

$(\frac{3 \sqrt{2}}{2}, \frac{2 \cdot (1 - 1)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{3 \sqrt{2}}{2}, \frac{2 \cdot (1 - 1)}{2 (1)})$

Cancel the common factor.

$(\frac{3 \sqrt{2}}{2}, \frac{2 \cdot (1 - 1)}{2 \cdot 1})$

Rewrite the expression.

$(\frac{3 \sqrt{2}}{2}, \frac{1 - 1}{1})$

Divide $1 - 1$ by $1$ .

$(\frac{3 \sqrt{2}}{2}, 1 - 1)$

Step 7

Subtract $1$ from $1$ .

$(\frac{3 \sqrt{2}}{2}, 0)$

Step 8