Find the Oxidation Numbers NO_3

$N O_{3}$

Step 1

Since $N$ is in column $5$ of the periodic table, it will share $5$ electrons and use an oxidation state of $5$ .

$N = 1 (5) = 5$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 3 (- 2) = - 6$

Step 3

This is the full list of oxidation states for this molecule.

$N = 5, O = - 6$