Find the Perpendicular Line y=3/2x and passes through the point (2,3)

$y = \frac{3}{2} x$ and passes through the point $(2, 3)$

Find the slope when $y = \frac{3}{2} x$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $\frac{3}{2}$ and $x$ .

$y = \frac{3 x}{2}$

Reorder terms.

$y = \frac{3}{2} x$

Using the slope-intercept form, the slope is $\frac{3}{2}$ .

$m = \frac{3}{2}$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{3}{2}}$

Simplify $- \frac{1}{\frac{3}{2}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{2}{3}))$

Multiply $\frac{2}{3}$ by $1$ .

$m_{perpendicular} = - \frac{2}{3}$

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{2}{3}$ and a given point $(2, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = - \frac{2}{3} \cdot (x - (2))$

Simplify the equation and keep it in point-slope form.

$y - 3 = - \frac{2}{3} \cdot (x - 2)$

Write in $y = m x + b$ form.

Solve for $y$ .

Simplify $- \frac{2}{3} \cdot (x - 2)$ .

Rewrite.

$y - 3 = 0 + 0 - \frac{2}{3} \cdot (x - 2)$

Simplify by adding zeros.

$y - 3 = - \frac{2}{3} \cdot (x - 2)$

Apply the distributive property.

$y - 3 = - \frac{2}{3} x - \frac{2}{3} \cdot - 2$

Combine $x$ and $\frac{2}{3}$ .

$y - 3 = - \frac{x \cdot 2}{3} - \frac{2}{3} \cdot - 2$

Multiply $- \frac{2}{3} \cdot - 2$ .

Multiply $- 2$ by $- 1$ .

$y - 3 = - \frac{x \cdot 2}{3} + 2 (\frac{2}{3})$

Combine $2$ and $\frac{2}{3}$ .

$y - 3 = - \frac{x \cdot 2}{3} + \frac{2 \cdot 2}{3}$

Multiply $2$ by $2$ .

$y - 3 = - \frac{x \cdot 2}{3} + \frac{4}{3}$

Move $2$ to the left of $x$ .

$y - 3 = - \frac{2 x}{3} + \frac{4}{3}$

Move all terms not containing $y$ to the right side of the equation.

Add $3$ to both sides of the equation.

$y = - \frac{2 x}{3} + \frac{4}{3} + 3$

To write $3$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$y = - \frac{2 x}{3} + \frac{4}{3} + 3 \cdot \frac{3}{3}$

Combine $3$ and $\frac{3}{3}$ .

$y = - \frac{2 x}{3} + \frac{4}{3} + \frac{3 \cdot 3}{3}$

Combine the numerators over the common denominator.

$y = - \frac{2 x}{3} + \frac{4 + 3 \cdot 3}{3}$

Simplify the numerator.

Multiply $3$ by $3$ .

$y = - \frac{2 x}{3} + \frac{4 + 9}{3}$

Add $4$ and $9$ .

$y = - \frac{2 x}{3} + \frac{13}{3}$

Reorder terms.

$y = - (\frac{2}{3} x) + \frac{13}{3}$

Remove parentheses.

$y = - \frac{2}{3} x + \frac{13}{3}$

Find the Perpendicular Line y=3/2x and passes through the point (2,3)

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