Find the Product (x+4)^3

${(x + 4)}^{3}$

Use the Binomial Theorem.

$x^{3} + 3 x^{2} \cdot 4 + 3 x \cdot 4^{2} + 4^{3}$

Simplify each term.

Multiply $4$ by $3$ .

$x^{3} + 12 x^{2} + 3 x \cdot 4^{2} + 4^{3}$

Raise $4$ to the power of $2$ .

$x^{3} + 12 x^{2} + 3 x \cdot 16 + 4^{3}$

Multiply $16$ by $3$ .

$x^{3} + 12 x^{2} + 48 x + 4^{3}$

Raise $4$ to the power of $3$ .

$x^{3} + 12 x^{2} + 48 x + 64$