Find the Quadratic Equation (36,4)

$(36, 4)$

Step 1

$x = 36$ and $x = 4$ are the two real distinct solutions for the quadratic equation, which means that $x - 36$ and $x - 4$ are the factors of the quadratic equation.

$(x - 36) (x - 4) = 0$

Step 2

Expand $(x - 36) (x - 4)$ using the FOIL Method.

Apply the distributive property.

$x (x - 4) - 36 (x - 4) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 4 - 36 (x - 4) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 4 - 36 x - 36 \cdot - 4 = 0$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 4 - 36 x - 36 \cdot - 4 = 0$

Move $- 4$ to the left of $x$ .

$x^{2} - 4 \cdot x - 36 x - 36 \cdot - 4 = 0$

Multiply $- 36$ by $- 4$ .

$x^{2} - 4 x - 36 x + 144 = 0$

Subtract $36 x$ from $- 4 x$ .

$x^{2} - 40 x + 144 = 0$

Step 4

The standard quadratic equation using the given set of solutions ${36, 4}$ is $y = x^{2} - 40 x + 144$ .

$y = x^{2} - 40 x + 144$

Step 5

Find the Quadratic Equation (36,4)

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