Find the Quadratic Equation (4,1)

$(4, 1)$

Step 1

$x = 4$ and $x = 1$ are the two real distinct solutions for the quadratic equation, which means that $x - 4$ and $x - 1$ are the factors of the quadratic equation.

$(x - 4) (x - 1) = 0$

Step 2

Expand $(x - 4) (x - 1)$ using the FOIL Method.

Apply the distributive property.

$x (x - 1) - 4 (x - 1) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 1 - 4 (x - 1) = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Move $- 1$ to the left of $x$ .

$x^{2} - 1 \cdot x - 4 x - 4 \cdot - 1 = 0$

Rewrite $- 1 x$ as $- x$ .

$x^{2} - x - 4 x - 4 \cdot - 1 = 0$

Multiply $- 4$ by $- 1$ .

$x^{2} - x - 4 x + 4 = 0$

Subtract $4 x$ from $- x$ .

$x^{2} - 5 x + 4 = 0$

Step 4

The standard quadratic equation using the given set of solutions ${4, 1}$ is $y = x^{2} - 5 x + 4$ .

$y = x^{2} - 5 x + 4$

Step 5

Find the Quadratic Equation (4,1)

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