Find the Quadratic Equation 6 , -8

$6$ , $- 8$

Step 1

$x = 6$ and $x = - 8$ are the two real distinct solutions for the quadratic equation, which means that $x - 6$ and $x + 8$ are the factors of the quadratic equation.

$(x - 6) (x + 8) = 0$

Step 2

Expand $(x - 6) (x + 8)$ using the FOIL Method.

Apply the distributive property.

$x (x + 8) - 6 (x + 8) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 8 - 6 (x + 8) = 0$

Apply the distributive property.

$x \cdot x + x \cdot 8 - 6 x - 6 \cdot 8 = 0$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 8 - 6 x - 6 \cdot 8 = 0$

Move $8$ to the left of $x$ .

$x^{2} + 8 \cdot x - 6 x - 6 \cdot 8 = 0$

Multiply $- 6$ by $8$ .

$x^{2} + 8 x - 6 x - 48 = 0$

Subtract $6 x$ from $8 x$ .

$x^{2} + 2 x - 48 = 0$

Step 4

The standard quadratic equation using the given set of solutions ${6, - 8}$ is $y = x^{2} + 2 x - 48$ .

$y = x^{2} + 2 x - 48$

Step 5

Find the Quadratic Equation 6 , -8

Related Questions

Support LCMGCF.com by disabling your adblocker.