Find the Roots (Zeros) f(x)=x^2+2x-35

$f (x) = x^{2} + 2 x - 35$

Step 1

Set $x^{2} + 2 x - 35$ equal to $0$ .

$x^{2} + 2 x - 35 = 0$

Step 2

Solve for $x$ .

Factor $x^{2} + 2 x - 35$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 35$ and whose sum is $2$ .

$- 5, 7$

Write the factored form using these integers.

$(x - 5) (x + 7) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$x + 7 = 0$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Set $x + 7$ equal to $0$ and solve for $x$ .

Set $x + 7$ equal to $0$ .

$x + 7 = 0$

Subtract $7$ from both sides of the equation.

$x = - 7$

The final solution is all the values that make $(x - 5) (x + 7) = 0$ true.

$x = 5, - 7$

Step 3

Find the Roots (Zeros) f(x)=x^2+2x-35

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