Find the Roots (Zeros) g(x)=(x+3)/(x^2+2x-3)

$g (x) = \frac{x + 3}{x^{2} + 2 x - 3}$

Step 1

Set $\frac{x + 3}{x^{2} + 2 x - 3}$ equal to $0$ .

$\frac{x + 3}{x^{2} + 2 x - 3} = 0$

Step 2

Solve for $x$ .

Set the numerator equal to zero.

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Exclude the solutions that do not make $\frac{x + 3}{x^{2} + 2 x - 3} = 0$ true.

$No solution$