Find the Second Term a_n=(-1)^n(13n-6)

$a_{n} = {(- 1)}^{n} (13 n - 6)$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = {(- 1)}^{2} (13 (2) - 6)$

Step 2

Raise $- 1$ to the power of $2$ .

$a_{2} = 1 (13 (2) - 6)$

Step 3

Multiply $13 (2) - 6$ by $1$ .

$a_{2} = 13 (2) - 6$

Step 4

Multiply $13$ by $2$ .

$a_{2} = 26 - 6$

Step 5

Subtract $6$ from $26$ .

$a_{2} = 20$