Find the Slope and y-intercept 8x-4y-12=0

$8 x - 4 y - 12 = 0$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Move all terms not containing $y$ to the right side of the equation.

Subtract $8 x$ from both sides of the equation.

$- 4 y - 12 = - 8 x$

Add $12$ to both sides of the equation.

$- 4 y = - 8 x + 12$

Divide each term in $- 4 y = - 8 x + 12$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 8 x + 12$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 8 x}{- 4} + \frac{12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 8 x}{- 4} + \frac{12}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 8 x}{- 4} + \frac{12}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8 x$ .

$y = \frac{- 4 (2 x)}{- 4} + \frac{12}{- 4}$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = \frac{- 4 (2 x)}{- 4 (1)} + \frac{12}{- 4}$

Cancel the common factor.

$y = \frac{- 4 (2 x)}{- 4 \cdot 1} + \frac{12}{- 4}$

Rewrite the expression.

$y = \frac{2 x}{1} + \frac{12}{- 4}$

Divide $2 x$ by $1$ .

$y = 2 x + \frac{12}{- 4}$

Divide $12$ by $- 4$ .

$y = 2 x - 3$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 2$

$b = - 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $2$

y-intercept: $(0, - 3)$

Slope: $2$

y-intercept: $(0, - 3)$

Step 3

Find the Slope and y-intercept 8x-4y-12=0

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