Find the Slope of a Perpendicular Line y=-1/5x+2

$y = - \frac{1}{5} x + 2$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $x$ and $\frac{1}{5}$ .

$y = - \frac{x}{5} + 2$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{1}{5} x) + 2$

Remove parentheses.

$y = - \frac{1}{5} x + 2$

Using the slope-intercept form, the slope is $- \frac{1}{5}$ .

$m = - \frac{1}{5}$

The equation of a perpendicular line to $y = - \frac{1}{5} x + 2$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{1}{5}}$

Simplify the result.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{1}{5}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{1}{5}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 \cdot 5$

Multiply $5$ by $1$ .

$m_{perpendicular} = - (- 1 \cdot 5)$

Multiply $- 1$ by $5$ .

$m_{perpendicular} = 5$

Multiply $- 1$ by $- 5$ .

$m_{perpendicular} = 5$