Find the Standard Form of the Parabola y=(x-3)^2+36

$y = {(x - 3)}^{2} + 36$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

${(x - 3)}^{2} + 36 = y$

Step 2

Subtract $36$ from both sides of the equation.

${(x - 3)}^{2} = y - 36$