Find the Variables [[6,5],[5,4]][[x],[y]]=[[2],[1]]

$[\begin{array}{c} 6 & 5 \\ 5 & 4 \end{array}] [\begin{array}{c} x \\ y \end{array}] = [\begin{array}{c} 2 \\ 1 \end{array}]$

Simplify the left side of the equation.

Multiply each row in the first matrix by each column in the second matrix.

$[\begin{array}{c} 6 \cdot x + 5 \cdot y \\ 5 \cdot x + 4 \cdot y \end{array}] = [\begin{array}{c} 2 \\ 1 \end{array}]$

Simplify each element of the matrix by multiplying out all the expressions.

$[\begin{array}{c} 6 x + 5 y \\ 5 x + 4 y \end{array}] = [\begin{array}{c} 2 \\ 1 \end{array}]$

The matrix equation can be written as a set of equations.

$6 x + 5 y = 2$

$5 x + 4 y = 1$

Solve for $x$ in $6 x + 5 y = 2$ .

Subtract $5 y$ from both sides of the equation.

$6 x = 2 - 5 y$

$5 x + 4 y = 1$

Divide each term in $6 x = 2 - 5 y$ by $6$ and simplify.

Divide each term in $6 x = 2 - 5 y$ by $6$ .

$\frac{6 x}{6} = \frac{2}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{2}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Divide $x$ by $1$ .

$x = \frac{2}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{2}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{2}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Simplify the right side.

Simplify each term.

Cancel the common factor of $2$ and $6$ .

Factor $2$ out of $2$ .

$x = \frac{2 (1)}{6} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Cancel the common factors.

Factor $2$ out of $6$ .

$x = \frac{2 \cdot 1}{2 \cdot 3} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Cancel the common factor.

$x = \frac{2 \cdot 1}{2 \cdot 3} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Rewrite the expression.

$x = \frac{1}{3} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} + \frac{- 5 y}{6}$

$5 x + 4 y = 1$

Move the negative in front of the fraction.

$x = \frac{1}{3} - \frac{5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$5 x + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$5 x + 4 y = 1$

Replace all occurrences of $x$ with $\frac{1}{3} - \frac{5 y}{6}$ in each equation.

Replace all occurrences of $x$ in $5 x + 4 y = 1$ with $\frac{1}{3} - \frac{5 y}{6}$ .

$5 (\frac{1}{3} - \frac{5 y}{6}) + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Simplify the left side.

Simplify $5 (\frac{1}{3} - \frac{5 y}{6}) + 4 y$ .

Simplify each term.

Apply the distributive property.

$5 (\frac{1}{3}) + 5 (- \frac{5 y}{6}) + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Combine $5$ and $\frac{1}{3}$ .

$\frac{5}{3} + 5 (- \frac{5 y}{6}) + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply $5 (- \frac{5 y}{6})$ .

Multiply $- 1$ by $5$ .

$\frac{5}{3} - 5 \frac{5 y}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Combine $- 5$ and $\frac{5 y}{6}$ .

$\frac{5}{3} + \frac{- 5 (5 y)}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply $5$ by $- 5$ .

$\frac{5}{3} + \frac{- 25 y}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} + \frac{- 25 y}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Move the negative in front of the fraction.

$\frac{5}{3} - \frac{25 y}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} - \frac{25 y}{6} + 4 y = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

To write $4 y$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$\frac{5}{3} - \frac{25 y}{6} + 4 y \cdot \frac{6}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Simplify terms.

Combine $4 y$ and $\frac{6}{6}$ .

$\frac{5}{3} - \frac{25 y}{6} + \frac{4 y \cdot 6}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Combine the numerators over the common denominator.

$\frac{5}{3} + \frac{- 25 y + 4 y \cdot 6}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} + \frac{- 25 y + 4 y \cdot 6}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Simplify each term.

Simplify the numerator.

Factor $y$ out of $- 25 y + 4 y \cdot 6$ .

Factor $y$ out of $- 25 y$ .

$\frac{5}{3} + \frac{y \cdot - 25 + 4 y \cdot 6}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Factor $y$ out of $4 y \cdot 6$ .

$\frac{5}{3} + \frac{y \cdot - 25 + y (4 \cdot 6)}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Factor $y$ out of $y \cdot - 25 + y (4 \cdot 6)$ .

$\frac{5}{3} + \frac{y (- 25 + 4 \cdot 6)}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} + \frac{y (- 25 + 4 \cdot 6)}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply $4$ by $6$ .

$\frac{5}{3} + \frac{y (- 25 + 24)}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Add $- 25$ and $24$ .

$\frac{5}{3} + \frac{y \cdot - 1}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} + \frac{y \cdot - 1}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Move $- 1$ to the left of $y$ .

$\frac{5}{3} + \frac{- 1 \cdot y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Move the negative in front of the fraction.

$\frac{5}{3} - \frac{y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} - \frac{y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} - \frac{y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} - \frac{y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

$\frac{5}{3} - \frac{y}{6} = 1$

$x = \frac{1}{3} - \frac{5 y}{6}$

Solve for $y$ in $\frac{5}{3} - \frac{y}{6} = 1$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $\frac{5}{3}$ from both sides of the equation.

$- \frac{y}{6} = 1 - \frac{5}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

Write $1$ as a fraction with a common denominator.

$- \frac{y}{6} = \frac{3}{3} - \frac{5}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

Combine the numerators over the common denominator.

$- \frac{y}{6} = \frac{3 - 5}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

Subtract $5$ from $3$ .

$- \frac{y}{6} = \frac{- 2}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

Move the negative in front of the fraction.

$- \frac{y}{6} = - \frac{2}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

$- \frac{y}{6} = - \frac{2}{3}$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply both sides of the equation by $- 6$ .

$- 6 (- \frac{y}{6}) = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 6 (- \frac{y}{6})$ .

Cancel the common factor of $6$ .

Move the leading negative in $- \frac{y}{6}$ into the numerator.

$- 6 \frac{- y}{6} = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Factor $6$ out of $- 6$ .

$6 (- 1) (\frac{- y}{6}) = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Cancel the common factor.

$6 \cdot (- 1 \frac{- y}{6}) = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Rewrite the expression.

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply $y$ by $1$ .

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = - 6 (- \frac{2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Simplify the right side.

Simplify $- 6 (- \frac{2}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$y = - 6 (\frac{- 2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Factor $3$ out of $- 6$ .

$y = 3 (- 2) (\frac{- 2}{3})$

$x = \frac{1}{3} - \frac{5 y}{6}$

Cancel the common factor.

$y = 3 \cdot (- 2 (\frac{- 2}{3}))$

$x = \frac{1}{3} - \frac{5 y}{6}$

Rewrite the expression.

$y = - 2 \cdot - 2$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = - 2 \cdot - 2$

$x = \frac{1}{3} - \frac{5 y}{6}$

Multiply $- 2$ by $- 2$ .

$y = 4$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = 4$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = 4$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = 4$

$x = \frac{1}{3} - \frac{5 y}{6}$

$y = 4$

$x = \frac{1}{3} - \frac{5 y}{6}$

Replace all occurrences of $y$ with $4$ in each equation.

Replace all occurrences of $y$ in $x = \frac{1}{3} - \frac{5 y}{6}$ with $4$ .

$x = \frac{1}{3} - \frac{5 (4)}{6}$

$y = 4$

Simplify the right side.

Simplify $\frac{1}{3} - \frac{5 (4)}{6}$ .

Simplify each term.

Cancel the common factor of $4$ and $6$ .

Factor $2$ out of $5 (4)$ .

$x = \frac{1}{3} - \frac{2 (5 \cdot (2))}{6}$

$y = 4$

Cancel the common factors.

Factor $2$ out of $6$ .

$x = \frac{1}{3} - \frac{2 (5 \cdot (2))}{2 (3)}$

$y = 4$

Cancel the common factor.

$x = \frac{1}{3} - \frac{2 (5 \cdot (2))}{2 \cdot 3}$

$y = 4$

Rewrite the expression.

$x = \frac{1}{3} - \frac{5 \cdot (2)}{3}$

$y = 4$

$x = \frac{1}{3} - \frac{5 \cdot (2)}{3}$

$y = 4$

$x = \frac{1}{3} - \frac{5 \cdot (2)}{3}$

$y = 4$

Multiply $5$ by $2$ .

$x = \frac{1}{3} - \frac{10}{3}$

$y = 4$

$x = \frac{1}{3} - \frac{10}{3}$

$y = 4$

Combine fractions.

Combine the numerators over the common denominator.

$x = \frac{1 - 10}{3}$

$y = 4$

Simplify the expression.

Subtract $10$ from $1$ .

$x = \frac{- 9}{3}$

$y = 4$

Divide $- 9$ by $3$ .

$x = - 3$

$y = 4$

$x = - 3$

$y = 4$

$x = - 3$

$y = 4$

$x = - 3$

$y = 4$

$x = - 3$

$y = 4$

$x = - 3$

$y = 4$

List all of the solutions.

$x = - 3, y = 4$

Find the Variables [[6,5],[5,4]][[x],[y]]=[[2],[1]]

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