Find the Vertex f(x)=2x^2+10x+14

$f (x) = 2 x^{2} + 10 x + 14$

Step 1

Rewrite the equation in vertex form.

Complete the square for $2 x^{2} + 10 x + 14$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 2$

$b = 10$

$c = 14$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{10}{2 \cdot 2}$

Cancel the common factor of $10$ and $2$ .

Factor $2$ out of $10$ .

$d = \frac{2 \cdot 5}{2 \cdot 2}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 2$ .

$d = \frac{2 \cdot 5}{2 (2)}$

Cancel the common factor.

$d = \frac{2 \cdot 5}{2 \cdot 2}$

Rewrite the expression.

$d = \frac{5}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 14 - \frac{10^{2}}{4 \cdot 2}$

Simplify the right side.

Simplify each term.

Raise $10$ to the power of $2$ .

$e = 14 - \frac{100}{4 \cdot 2}$

Multiply $4$ by $2$ .

$e = 14 - \frac{100}{8}$

Cancel the common factor of $100$ and $8$ .

Factor $4$ out of $100$ .

$e = 14 - \frac{4 (25)}{8}$

Cancel the common factors.

Factor $4$ out of $8$ .

$e = 14 - \frac{4 \cdot 25}{4 \cdot 2}$

Cancel the common factor.

$e = 14 - \frac{4 \cdot 25}{4 \cdot 2}$

Rewrite the expression.

$e = 14 - \frac{25}{2}$

To write $14$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$e = 14 \cdot \frac{2}{2} - \frac{25}{2}$

Combine $14$ and $\frac{2}{2}$ .

$e = \frac{14 \cdot 2}{2} - \frac{25}{2}$

Combine the numerators over the common denominator.

$e = \frac{14 \cdot 2 - 25}{2}$

Simplify the numerator.

Multiply $14$ by $2$ .

$e = \frac{28 - 25}{2}$

Subtract $25$ from $28$ .

$e = \frac{3}{2}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $2 {(x + \frac{5}{2})}^{2} + \frac{3}{2}$ .

$2 {(x + \frac{5}{2})}^{2} + \frac{3}{2}$

Set $y$ equal to the new right side.

$y = 2 {(x + \frac{5}{2})}^{2} + \frac{3}{2}$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 2$

$h = - \frac{5}{2}$

$k = \frac{3}{2}$

Step 3

Find the vertex $(h, k)$ .

$(- \frac{5}{2}, \frac{3}{2})$

Step 4

Find the Vertex f(x)=2x^2+10x+14

Related Questions

Support LCMGCF.com by disabling your adblocker.