Find the Vertex (x-6)^2=y+7

${(x - 6)}^{2} = y + 7$

Step 1

Isolate $y$ to the left side of the equation.

Rewrite the equation as $y + 7 = {(x - 6)}^{2}$ .

$y + 7 = {(x - 6)}^{2}$

Subtract $7$ from both sides of the equation.

$y = {(x - 6)}^{2} - 7$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = 6$

$k = - 7$

Step 3

Find the vertex $(h, k)$ .

$(6, - 7)$

Step 4