Find the x and y Intercepts f(x)=(x^2+2x-48)/(3x^2-18x)

$f (x) = \frac{x^{2} + 2 x - 48}{3 x^{2} - 18 x}$

Step 1

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{x^{2} + 2 x - 48}{3 x^{2} - 18 x}$

Solve the equation.

Set the numerator equal to zero.

$x^{2} + 2 x - 48 = 0$

Solve the equation for $x$ .

Factor $x^{2} + 2 x - 48$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 48$ and whose sum is $2$ .

$- 6, 8$

Write the factored form using these integers.

$(x - 6) (x + 8) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 6 = 0$

$x + 8 = 0$

Set $x - 6$ equal to $0$ and solve for $x$ .

Set $x - 6$ equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

Set $x + 8$ equal to $0$ and solve for $x$ .

Set $x + 8$ equal to $0$ .

$x + 8 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

The final solution is all the values that make $(x - 6) (x + 8) = 0$ true.

$x = 6, - 8$

Exclude the solutions that do not make $0 = \frac{x^{2} + 2 x - 48}{3 x^{2} - 18 x}$ true.

$x = - 8$

x-intercept(s) in point form.

x-intercept(s): $(- 8, 0)$

Step 2

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{{(0)}^{2} + 2 (0) - 48}{3 {(0)}^{2} - 18 \cdot 0}$

The equation has an undefined fraction.

Undefined

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

y-intercept(s): $None$

Step 3

List the intersections.

x-intercept(s): $(- 8, 0)$

y-intercept(s): $None$

Step 4

Find the x and y Intercepts f(x)=(x^2+2x-48)/(3x^2-18x)

Related Questions

Support LCMGCF.com by disabling your adblocker.