Find the x and y Intercepts (x-2)(-x-4)=y

$(x - 2) (- x - 4) = y$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$(x - 2) (- x - 4) = 0$

Solve the equation.

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 2 = 0$

$- x - 4 = 0$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Set $- x - 4$ equal to $0$ and solve for $x$ .

Set $- x - 4$ equal to $0$ .

$- x - 4 = 0$

Solve $- x - 4 = 0$ for $x$ .

Add $4$ to both sides of the equation.

$- x = 4$

Divide each term in $- x = 4$ by $- 1$ and simplify.

Divide each term in $- x = 4$ by $- 1$ .

$\frac{- x}{- 1} = \frac{4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{4}{- 1}$

Divide $x$ by $1$ .

$x = \frac{4}{- 1}$

Simplify the right side.

Divide $4$ by $- 1$ .

$x = - 4$

The final solution is all the values that make $(x - 2) (- x - 4) = 0$ true.

$x = 2, - 4$

x-intercept(s) in point form.

x-intercept(s): $(2, 0), (- 4, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$((0) - 2) (- (0) - 4) = y$

Solve the equation.

Rewrite the equation as $y = ((0) - 2) (- (0) - 4)$ .

$y = ((0) - 2) (- (0) - 4)$

Simplify $((0) - 2) (- (0) - 4)$ .

Subtract $2$ from $0$ .

$y = - 2 (- (0) - 4)$

Multiply $- 1$ by $0$ .

$y = - 2 (0 - 4)$

Subtract $4$ from $0$ .

$y = - 2 \cdot - 4$

Multiply $- 2$ by $- 4$ .

$y = 8$

y-intercept(s) in point form.

y-intercept(s): $(0, 8)$

List the intersections.

x-intercept(s): $(2, 0), (- 4, 0)$

y-intercept(s): $(0, 8)$

Find the x and y Intercepts (x-2)(-x-4)=y

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