Find the x and y Intercepts y=-x^2+6x+1

$y = - x^{2} + 6 x + 1$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = - x^{2} + 6 x + 1$

Solve the equation.

Rewrite the equation as $- x^{2} + 6 x + 1 = 0$ .

$- x^{2} + 6 x + 1 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = - 1$ , $b = 6$ , and $c = 1$ into the quadratic formula and solve for $x$ .

$\frac{- 6 \pm \sqrt{6^{2} - 4 \cdot (- 1 \cdot 1)}}{2 \cdot - 1}$

Simplify.

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot - 1 \cdot 1}}{2 \cdot - 1}$

Multiply $- 4$ by $- 1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4 \cdot 1}}{2 \cdot - 1}$

Multiply $4$ by $1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4}}{2 \cdot - 1}$

Add $36$ and $4$ .

$x = \frac{- 6 \pm \sqrt{40}}{2 \cdot - 1}$

Rewrite $40$ as $2^{2} \cdot 10$ .

Factor $4$ out of $40$ .

$x = \frac{- 6 \pm \sqrt{4 (10)}}{2 \cdot - 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 6 \pm \sqrt{2^{2} \cdot 10}}{2 \cdot - 1}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm 2 \sqrt{10}}{2 \cdot - 1}$

Multiply $2$ by $- 1$ .

$x = \frac{- 6 \pm 2 \sqrt{10}}{- 2}$

Simplify $\frac{- 6 \pm 2 \sqrt{10}}{- 2}$ .

$x = 3 \pm \sqrt{10}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot - 1 \cdot 1}}{2 \cdot - 1}$

Multiply $- 4$ by $- 1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4 \cdot 1}}{2 \cdot - 1}$

Multiply $4$ by $1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4}}{2 \cdot - 1}$

Add $36$ and $4$ .

$x = \frac{- 6 \pm \sqrt{40}}{2 \cdot - 1}$

Rewrite $40$ as $2^{2} \cdot 10$ .

Factor $4$ out of $40$ .

$x = \frac{- 6 \pm \sqrt{4 (10)}}{2 \cdot - 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 6 \pm \sqrt{2^{2} \cdot 10}}{2 \cdot - 1}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm 2 \sqrt{10}}{2 \cdot - 1}$

Multiply $2$ by $- 1$ .

$x = \frac{- 6 \pm 2 \sqrt{10}}{- 2}$

Simplify $\frac{- 6 \pm 2 \sqrt{10}}{- 2}$ .

$x = 3 \pm \sqrt{10}$

Change the $\pm$ to $+$ .

$x = 3 + \sqrt{10}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot - 1 \cdot 1}}{2 \cdot - 1}$

Multiply $- 4$ by $- 1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4 \cdot 1}}{2 \cdot - 1}$

Multiply $4$ by $1$ .

$x = \frac{- 6 \pm \sqrt{36 + 4}}{2 \cdot - 1}$

Add $36$ and $4$ .

$x = \frac{- 6 \pm \sqrt{40}}{2 \cdot - 1}$

Rewrite $40$ as $2^{2} \cdot 10$ .

Factor $4$ out of $40$ .

$x = \frac{- 6 \pm \sqrt{4 (10)}}{2 \cdot - 1}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{- 6 \pm \sqrt{2^{2} \cdot 10}}{2 \cdot - 1}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm 2 \sqrt{10}}{2 \cdot - 1}$

Multiply $2$ by $- 1$ .

$x = \frac{- 6 \pm 2 \sqrt{10}}{- 2}$

Simplify $\frac{- 6 \pm 2 \sqrt{10}}{- 2}$ .

$x = 3 \pm \sqrt{10}$

Change the $\pm$ to $-$ .

$x = 3 - \sqrt{10}$

The final answer is the combination of both solutions.

$x = 3 + \sqrt{10}, 3 - \sqrt{10}$

x-intercept(s) in point form.

x-intercept(s): $(3 + \sqrt{10}, 0), (3 - \sqrt{10}, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = - {(0)}^{2} + 6 (0) + 1$

Solve the equation.

Remove parentheses.

$y = - 0^{2} + 6 (0) + 1$

Remove parentheses.

$y = - {(0)}^{2} + 6 (0) + 1$

Simplify $- {(0)}^{2} + 6 (0) + 1$ .

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$y = - 0 + 6 (0) + 1$

Multiply $- 1$ by $0$ .

$y = 0 + 6 (0) + 1$

Multiply $6$ by $0$ .

$y = 0 + 0 + 1$

Simplify by adding numbers.

Add $0$ and $0$ .

$y = 0 + 1$

Add $0$ and $1$ .

$y = 1$

y-intercept(s) in point form.

y-intercept(s): $(0, 1)$

List the intersections.

x-intercept(s): $(3 + \sqrt{10}, 0), (3 - \sqrt{10}, 0)$

y-intercept(s): $(0, 1)$

Find the x and y Intercepts y=-x^2+6x+1

Related Questions

Support LCMGCF.com by disabling your adblocker.