Find Three Ordered Pair Solutions 5x+y=14

$5 x + y = 14$

Step 1

Subtract $5 x$ from both sides of the equation.

$y = 14 - 5 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 14 - 5 \cdot 0$

Simplify $14 - 5 \cdot 0$ .

Multiply $- 5$ by $0$ .

$y = 14 + 0$

Add $14$ and $0$ .

$y = 14$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 14)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 14 - 5 \cdot 1$

Simplify $14 - 5 \cdot 1$ .

Multiply $- 5$ by $1$ .

$y = 14 - 5$

Subtract $5$ from $14$ .

$y = 9$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 9)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 14 - 5 \cdot 2$

Simplify $14 - 5 \cdot 2$ .

Multiply $- 5$ by $2$ .

$y = 14 - 10$

Subtract $10$ from $14$ .

$y = 4$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 4)$

Step 6

These are three possible solutions to the equation.

$(0, 14), (1, 9), (2, 4)$

Step 7