Find Where Undefined/Discontinuous -2/(9x^3)*6/(5x^5)

$\frac{- 2}{9 x^{3}} \cdot \frac{6}{5 x^{5}}$

Step 1

Set the denominator in $\frac{- 2}{9 x^{3}}$ equal to $0$ to find where the expression is undefined.

$9 x^{3} = 0$

Step 2

Solve for $x$ .

Divide each term in $9 x^{3} = 0$ by $9$ and simplify.

Divide each term in $9 x^{3} = 0$ by $9$ .

$\frac{9 x^{3}}{9} = \frac{0}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x^{3}}{9} = \frac{0}{9}$

Divide $x^{3}$ by $1$ .

$x^{3} = \frac{0}{9}$

Simplify the right side.

Divide $0$ by $9$ .

$x^{3} = 0$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{0}$

Simplify $\sqrt[3]{0}$ .

Rewrite $0$ as $0^{3}$ .

$x = \sqrt[3]{0^{3}}$

Pull terms out from under the radical, assuming real numbers.

$x = 0$

Step 3

Set the denominator in $\frac{6}{5 x^{5}}$ equal to $0$ to find where the expression is undefined.

$5 x^{5} = 0$

Step 4

Solve for $x$ .

Divide each term in $5 x^{5} = 0$ by $5$ and simplify.

Divide each term in $5 x^{5} = 0$ by $5$ .

$\frac{5 x^{5}}{5} = \frac{0}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x^{5}}{5} = \frac{0}{5}$

Divide $x^{5}$ by $1$ .

$x^{5} = \frac{0}{5}$

Simplify the right side.

Divide $0$ by $5$ .

$x^{5} = 0$

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[5]{0}$

Simplify $\sqrt[5]{0}$ .

Rewrite $0$ as $0^{5}$ .

$x = \sqrt[5]{0^{5}}$

Pull terms out from under the radical, assuming real numbers.

$x = 0$

Step 5

Find Where Undefined/Discontinuous -2/(9x^3)*6/(5x^5)

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