Graph f(x)=2 square root of x+4

$f (x) = 2 \sqrt{x + 4}$

Step 1

Find the domain for $y = 2 \sqrt{x + 4}$ so that a list of $x$ values can be picked to find a list of points, which will help graphing the radical.

Set the radicand in $\sqrt{x + 4}$ greater than or equal to $0$ to find where the expression is defined.

$x + 4 \geq 0$

Subtract $4$ from both sides of the inequality.

$x \geq - 4$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 4, \infty)$

Set-Builder Notation:

${x | x \geq - 4}$

Interval Notation:

$[- 4, \infty)$

Set-Builder Notation:

${x | x \geq - 4}$

Step 2

To find the radical expression end point, substitute the $x$ value $- 4$ , which is the least value in the domain, into $f (x) = 2 \sqrt{x + 4}$ .

Replace the variable $x$ with $- 4$ in the expression.

$f (- 4) = 2 \sqrt{(- 4) + 4}$

Simplify the result.

Add $- 4$ and $4$ .

$f (- 4) = 2 \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$f (- 4) = 2 \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (- 4) = 2 \cdot 0$

Multiply $2$ by $0$ .

$f (- 4) = 0$

The final answer is $0$ .

$0$

Step 3

The radical expression end point is $(- 4, 0)$ .

$(- 4, 0)$

Step 4

Select a few $x$ values from the domain. It would be more useful to select the values so that they are next to the $x$ value of the radical expression end point.

Substitute the $x$ value $- 3$ into $f (x) = 2 \sqrt{x + 4}$ . In this case, the point is $(- 3, 2)$ .

Replace the variable $x$ with $- 3$ in the expression.

$f (- 3) = 2 \sqrt{(- 3) + 4}$

Simplify the result.

Add $- 3$ and $4$ .

$f (- 3) = 2 \sqrt{1}$

Any root of $1$ is $1$ .

$f (- 3) = 2 \cdot 1$

Multiply $2$ by $1$ .

$f (- 3) = 2$

The final answer is $2$ .

$y = 2$

Substitute the $x$ value $- 2$ into $f (x) = 2 \sqrt{x + 4}$ . In this case, the point is $(- 2, 2 \sqrt{2})$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = 2 \sqrt{(- 2) + 4}$

Simplify the result.

Add $- 2$ and $4$ .

$f (- 2) = 2 \sqrt{2}$

The final answer is $2 \sqrt{2}$ .

$y = 2 \sqrt{2}$

The square root can be graphed using the points around the vertex $(- 4, 0), (- 3, 2), (- 2, 2.83)$

$\begin{array}{c} x & y \\ - 4 & 0 \\ - 3 & 2 \\ - 2 & 2.83 \end{array}$

Step 5

Graph f(x)=2 square root of x+4

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