Graph f(x)=arccos(x)

$f (x) = \arccos (x)$

Step 1

Select a few points to graph.

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = \arccos (- 1)$

Simplify the result.

The exact value of $\arccos (- 1)$ is $π$ .

$f (- 1) = π$

The final answer is $π$ .

$π$

Find the point at $x = - \frac{1}{2}$ .

Replace the variable $x$ with $- \frac{1}{2}$ in the expression.

$f (- \frac{1}{2}) = \arccos (- \frac{1}{2})$

Simplify the result.

The exact value of $\arccos (- \frac{1}{2})$ is $\frac{2 π}{3}$ .

$f (- \frac{1}{2}) = \frac{2 π}{3}$

The final answer is $\frac{2 π}{3}$ .

$\frac{2 π}{3}$

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = \arccos (0)$

Simplify the result.

The exact value of $\arccos (0)$ is $\frac{π}{2}$ .

$f (0) = \frac{π}{2}$

The final answer is $\frac{π}{2}$ .

$\frac{π}{2}$

Find the point at $x = \frac{1}{2}$ .

Replace the variable $x$ with $\frac{1}{2}$ in the expression.

$f (\frac{1}{2}) = \arccos (\frac{1}{2})$

Simplify the result.

The exact value of $\arccos (\frac{1}{2})$ is $\frac{π}{3}$ .

$f (\frac{1}{2}) = \frac{π}{3}$

The final answer is $\frac{π}{3}$ .

$\frac{π}{3}$

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \arccos (1)$

Simplify the result.

The exact value of $\arccos (1)$ is $0$ .

$f (1) = 0$

The final answer is $0$ .

$0$

List the points in a table.

$\begin{array}{c} x & f (x) \\ - 1 & π \\ - \frac{1}{2} & \frac{2 π}{3} \\ 0 & \frac{π}{2} \\ \frac{1}{2} & \frac{π}{3} \\ 1 & 0 \end{array}$

Step 2

The trig function can be graphed using the points.

$\begin{array}{c} x & f (x) \\ - 1 & π \\ - \frac{1}{2} & \frac{2 π}{3} \\ 0 & \frac{π}{2} \\ \frac{1}{2} & \frac{π}{3} \\ 1 & 0 \end{array}$

Step 3

Graph f(x)=arccos(x)

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