Graph Using a Table of Values y=2^(x+1)

$y = 2^{x + 1}$

Step 1

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = 2^{(- 2) + 1}$

Step 2

Simplify $2^{(- 2) + 1}$ .

Add $- 2$ and $1$ .

$y = 2^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y = \frac{1}{2}$

Step 3

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = 2^{(- 1) + 1}$

Step 4

Simplify $2^{(- 1) + 1}$ .

Add $- 1$ and $1$ .

$y = 2^{0}$

Anything raised to $0$ is $1$ .

$y = 1$

Step 5

Substitute $0$ for $x$ and find the result for $y$ .

$y = 2^{(0) + 1}$

Step 6

Simplify $2^{(0) + 1}$ .

Add $0$ and $1$ .

$y = 2^{1}$

Evaluate the exponent.

$y = 2$

Step 7

Substitute $1$ for $x$ and find the result for $y$ .

$y = 2^{(1) + 1}$

Step 8

Simplify $2^{(1) + 1}$ .

Add $1$ and $1$ .

$y = 2^{2}$

Raise $2$ to the power of $2$ .

$y = 4$

Step 9

Substitute $2$ for $x$ and find the result for $y$ .

$y = 2^{(2) + 1}$

Step 10

Simplify $2^{(2) + 1}$ .

Add $2$ and $1$ .

$y = 2^{3}$

Raise $2$ to the power of $3$ .

$y = 8$

Step 11

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & \frac{1}{2} \\ - 1 & 1 \\ 0 & 2 \\ 1 & 4 \\ 2 & 8 \end{array}$

Step 12

Graph Using a Table of Values y=2^(x+1)

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