Graph -x^2+y>=-3

$- x^{2} + y \geq - 3$

Step 1

Add $x^{2}$ to both sides of the inequality.

$y \geq - 3 + x^{2}$

Step 2

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- 3$ and $x^{2}$ .

$y \geq x^{2} - 3$

The equation is not linear, so a constant slope does not exist.

Not Linear

Step 3

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- 3 + x^{2}$ .

$y \geq - 3 + x^{2}$

Step 4