Graph x=y^3

$x = y^{3}$

Step 1

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = \sqrt[3]{- 1}$

Simplify the result.

Remove parentheses.

$f (- 1) = \sqrt[3]{- 1}$

Rewrite $- 1$ as ${(- 1)}^{3}$ .

$f (- 1) = \sqrt[3]{{(- 1)}^{3}}$

Pull terms out from under the radical, assuming real numbers.

$f (- 1) = - 1$

The final answer is $- 1$ .

$- 1$

Convert $- 1$ to decimal.

$y = - 1$

Step 2

Find the point at $x = 0$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = \sqrt[3]{0}$

Simplify the result.

Remove parentheses.

$f (0) = \sqrt[3]{0}$

Rewrite $0$ as $0^{3}$ .

$f (0) = \sqrt[3]{0^{3}}$

Pull terms out from under the radical, assuming real numbers.

$f (0) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 3

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = \sqrt[3]{1}$

Simplify the result.

Remove parentheses.

$f (1) = \sqrt[3]{1}$

Any root of $1$ is $1$ .

$f (1) = 1$

The final answer is $1$ .

$1$

Convert $1$ to decimal.

$y = 1$

Step 4

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = \sqrt[3]{- 2}$

Simplify the result.

Remove parentheses.

$f (- 2) = \sqrt[3]{- 2}$

Rewrite $- 2$ as ${(- 1)}^{3} \cdot 2$ .

Rewrite $- 2$ as $- 1 (2)$ .

$f (- 2) = \sqrt[3]{- 1 \cdot 2}$

Rewrite $- 1$ as ${(- 1)}^{3}$ .

$f (- 2) = \sqrt[3]{{(- 1)}^{3} \cdot 2}$

Pull terms out from under the radical.

$f (- 2) = - 1 \sqrt[3]{2}$

Rewrite $- 1 \sqrt[3]{2}$ as $- \sqrt[3]{2}$ .

$f (- 2) = - \sqrt[3]{2}$

The final answer is $- \sqrt[3]{2}$ .

$- \sqrt[3]{2}$

Convert $- \sqrt[3]{2}$ to decimal.

$y = - 1.25992104$

Step 5

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = \sqrt[3]{2}$

Simplify the result.

Remove parentheses.

$f (2) = \sqrt[3]{2}$

The final answer is $\sqrt[3]{2}$ .

$\sqrt[3]{2}$

Convert $\sqrt[3]{2}$ to decimal.

$y = 1.25992104$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & - 1.26 \\ - 1 & - 1 \\ 0 & 0 \\ 1 & 1 \\ 2 & 1.26 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Not a polynomial

$\begin{array}{c} x & y \\ - 2 & - 1.26 \\ - 1 & - 1 \\ 0 & 0 \\ 1 & 1 \\ 2 & 1.26 \end{array}$

Step 8

Graph x=y^3

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