Graph y>1/4|x+1|+1

$y > \frac{1}{4} | x + 1 | + 1$

Combine $\frac{1}{4}$ and $| x + 1 |$ .

$y > \frac{| x + 1 |}{4} + 1$

Combine into one fraction.

Write $1$ as a fraction with a common denominator.

$y > \frac{| x + 1 |}{4} + \frac{4}{4}$

Combine the numerators over the common denominator.

$y > \frac{| x + 1 | + 4}{4}$