Graph y=2 log of x

$y = 2 \log (x)$

Step 1

Find the asymptotes.

Set the argument of the logarithm equal to zero.

$x^{2} = 0$

Solve for $x$ .

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$

The vertical asymptote occurs at $x = 0$ .

Vertical Asymptote: $x = 0$

Step 2

Find the point at $x = 1$ .

Replace the variable $x$ with $1$ in the expression.

$f (1) = 2 \log (1)$

Simplify the result.

Logarithm base $10$ of $1$ is $0$ .

$f (1) = 2 \cdot 0$

Multiply $2$ by $0$ .

$f (1) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$y = 0$

Step 3

Find the point at $x = 10$ .

Replace the variable $x$ with $10$ in the expression.

$f (10) = 2 \log (10)$

Simplify the result.

Logarithm base $10$ of $10$ is $1$ .

$f (10) = 2 \cdot 1$

Multiply $2$ by $1$ .

$f (10) = 2$

The final answer is $2$ .

$2$

Convert $2$ to decimal.

$y = 2$

Step 4

Find the point at $x = 2$ .

Replace the variable $x$ with $2$ in the expression.

$f (2) = 2 \log (2)$

Simplify the result.

Simplify $2 \log (2)$ by moving $2$ inside the logarithm.

$f (2) = \log (2^{2})$

Raise $2$ to the power of $2$ .

$f (2) = \log (4)$

The final answer is $\log (4)$ .

$\log (4)$

Convert $\log (4)$ to decimal.

$y = 0.60205999$

Step 5

The log function can be graphed using the vertical asymptote at $x = 0$ and the points $(1, 0), (10, 2), (2, 0.60205999)$ .

Vertical Asymptote: $x = 0$

$\begin{array}{c} x & y \\ 1 & 0 \\ 2 & 0.602 \\ 10 & 2 \end{array}$

Step 6

Graph y=2 log of x

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