Graph y<=-x+3 y<=x^2-3x

$y \leq - x + 3$ $y \leq x^{2} - 3 x$

Step 1

Graph $y \leq - x + 3$ .

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 3)$

Slope: $- 1$

y-intercept: $(0, 3)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- x + 3$ .

$y \leq - x + 3$

Step 2

Graph $y \leq x^{2} - 3 x$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x^{2} - 3 x$ .

$y \leq x^{2} - 3 x$

Step 3

Plot each graph on the same coordinate system.

$y \leq - x + 3$

$y \leq x^{2} - 3 x$

Step 4