Graph y=- log base 2 of -x

$y = - \log_{2} (- x)$

Find the asymptotes.

Set the argument of the logarithm equal to zero.

$- x = 0$

Divide each term in $- x = 0$ by $- 1$ and simplify.

Divide each term in $- x = 0$ by $- 1$ .

$\frac{- x}{- 1} = \frac{0}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{0}{- 1}$

Divide $x$ by $1$ .

$x = \frac{0}{- 1}$

Simplify the right side.

Divide $0$ by $- 1$ .

$x = 0$

The vertical asymptote occurs at $x = 0$ .

Vertical Asymptote: $x = 0$

Find the point at $x = - 1$ .

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - \log_{2} (- (- 1))$

Simplify the result.

Multiply $- 1$ by $- 1$ .

$f (- 1) = - \log_{2} (1)$

Logarithm base $2$ of $1$ is $0$ .

$f (- 1) = - 0$

Multiply $- 1$ by $0$ .

$f (- 1) = 0$

The final answer is $0$ .

$0$

Convert $0$ to decimal.

$= 0$

Find the point at $x = - 2$ .

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = - \log_{2} (- (- 2))$

Simplify the result.

Multiply $- 1$ by $- 2$ .

$f (- 2) = - \log_{2} (2)$

Logarithm base $2$ of $2$ is $1$ .

$f (- 2) = - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$f (- 2) = - 1$

The final answer is $- 1$ .

$- 1$

Convert $- 1$ to decimal.

$= - 1$

Find the point at $x = - 3$ .

Replace the variable $x$ with $- 3$ in the expression.

$f (- 3) = - \log_{2} (- (- 3))$

Simplify the result.

Multiply $- 1$ by $- 3$ .

$f (- 3) = - \log_{2} (3)$

The final answer is $- \log_{2} (3)$ .

$- \log_{2} (3)$

Convert $- \log_{2} (3)$ to decimal.

$= - 1.5849625$

The log function can be graphed using the vertical asymptote at $x = 0$ and the points $(- 1, 0), (- 2, - 1), (- 3, - 1.5849625)$ .

Vertical Asymptote: $x = 0$

$\begin{array}{c} x & y \\ - 3 & - 1.585 \\ - 2 & - 1 \\ - 1 & 0 \end{array}$

Graph y=- log base 2 of -x

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