Graph y=x^2+3x-5

$y = x^{2} + 3 x - 5$

Step 1

Find the properties of the given parabola.

Rewrite the equation in vertex form.

Complete the square for $x^{2} + 3 x - 5$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 3$

$c = - 5$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{3}{2 \cdot 1}$

Multiply $2$ by $1$ .

$d = \frac{3}{2}$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = - 5 - \frac{3^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $3$ to the power of $2$ .

$e = - 5 - \frac{9}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = - 5 - \frac{9}{4}$

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$e = - 5 \cdot \frac{4}{4} - \frac{9}{4}$

Combine $- 5$ and $\frac{4}{4}$ .

$e = \frac{- 5 \cdot 4}{4} - \frac{9}{4}$

Combine the numerators over the common denominator.

$e = \frac{- 5 \cdot 4 - 9}{4}$

Simplify the numerator.

Multiply $- 5$ by $4$ .

$e = \frac{- 20 - 9}{4}$

Subtract $9$ from $- 20$ .

$e = \frac{- 29}{4}$

Move the negative in front of the fraction.

$e = - \frac{29}{4}$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + \frac{3}{2})}^{2} - \frac{29}{4}$ .

${(x + \frac{3}{2})}^{2} - \frac{29}{4}$

Set $y$ equal to the new right side.

$y = {(x + \frac{3}{2})}^{2} - \frac{29}{4}$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = - \frac{3}{2}$

$k = - \frac{29}{4}$

Since the value of $a$ is positive, the parabola opens up.

Opens Up

Find the vertex $(h, k)$ .

$(- \frac{3}{2}, - \frac{29}{4})$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot 1}$

Cancel the common factor of $1$ .

Cancel the common factor.

$\frac{1}{4 \cdot 1}$

Rewrite the expression.

$\frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- \frac{3}{2}, - 7)$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - \frac{3}{2}$

Find the directrix.

The directrix of a parabola is the horizontal line found by subtracting $p$ from the y-coordinate $k$ of the vertex if the parabola opens up or down.

$y = k - p$

Substitute the known values of $p$ and $k$ into the formula and simplify.

$y = - \frac{15}{2}$

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: $(- \frac{3}{2}, - \frac{29}{4})$

Focus: $(- \frac{3}{2}, - 7)$

Axis of Symmetry: $x = - \frac{3}{2}$

Directrix: $y = - \frac{15}{2}$

Direction: Opens Up

Vertex: $(- \frac{3}{2}, - \frac{29}{4})$

Focus: $(- \frac{3}{2}, - 7)$

Axis of Symmetry: $x = - \frac{3}{2}$

Directrix: $y = - \frac{15}{2}$

Step 2

Select a few $x$ values, and plug them into the equation to find the corresponding $y$ values. The $x$ values should be selected around the vertex.

Replace the variable $x$ with $- 3$ in the expression.

$f (- 3) = {(- 3)}^{2} + 3 (- 3) - 5$

Simplify the result.

Simplify each term.

Raise $- 3$ to the power of $2$ .

$f (- 3) = 9 + 3 (- 3) - 5$

Multiply $3$ by $- 3$ .

$f (- 3) = 9 - 9 - 5$

Simplify by subtracting numbers.

Subtract $9$ from $9$ .

$f (- 3) = 0 - 5$

Subtract $5$ from $0$ .

$f (- 3) = - 5$

The final answer is $- 5$ .

$- 5$

The $y$ value at $x = - 3$ is $- 5$ .

$y = - 5$

Replace the variable $x$ with $- 4$ in the expression.

$f (- 4) = {(- 4)}^{2} + 3 (- 4) - 5$

Simplify the result.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$f (- 4) = 16 + 3 (- 4) - 5$

Multiply $3$ by $- 4$ .

$f (- 4) = 16 - 12 - 5$

Simplify by subtracting numbers.

Subtract $12$ from $16$ .

$f (- 4) = 4 - 5$

Subtract $5$ from $4$ .

$f (- 4) = - 1$

The final answer is $- 1$ .

$- 1$

The $y$ value at $x = - 4$ is $- 1$ .

$y = - 1$

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{2} + 3 (- 1) - 5$

Simplify the result.

Simplify each term.

Raise $- 1$ to the power of $2$ .

$f (- 1) = 1 + 3 (- 1) - 5$

Multiply $3$ by $- 1$ .

$f (- 1) = 1 - 3 - 5$

Simplify by subtracting numbers.

Subtract $3$ from $1$ .

$f (- 1) = - 2 - 5$

Subtract $5$ from $- 2$ .

$f (- 1) = - 7$

The final answer is $- 7$ .

$- 7$

The $y$ value at $x = - 1$ is $- 7$ .

$y = - 7$

Replace the variable $x$ with $0$ in the expression.

$f (0) = {(0)}^{2} + 3 (0) - 5$

Simplify the result.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = 0 + 3 (0) - 5$

Multiply $3$ by $0$ .

$f (0) = 0 + 0 - 5$

Simplify by adding and subtracting.

Add $0$ and $0$ .

$f (0) = 0 - 5$

Subtract $5$ from $0$ .

$f (0) = - 5$

The final answer is $- 5$ .

$- 5$

The $y$ value at $x = 0$ is $- 5$ .

$y = - 5$

Graph the parabola using its properties and the selected points.

$\begin{array}{c} x & y \\ - 4 & - 1 \\ - 3 & - 5 \\ - \frac{3}{2} & - \frac{29}{4} \\ - 1 & - 7 \\ 0 & - 5 \end{array}$

Step 3

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: $(- \frac{3}{2}, - \frac{29}{4})$

Focus: $(- \frac{3}{2}, - 7)$

Axis of Symmetry: $x = - \frac{3}{2}$

Directrix: $y = - \frac{15}{2}$

$\begin{array}{c} x & y \\ - 4 & - 1 \\ - 3 & - 5 \\ - \frac{3}{2} & - \frac{29}{4} \\ - 1 & - 7 \\ 0 & - 5 \end{array}$

Step 4

Graph y=x^2+3x-5

Related Questions

Support LCMGCF.com by disabling your adblocker.