Graph y>=-x-3

$y \geq - x - 3$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = - 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, - 3)$

Slope: $- 1$

y-intercept: $(0, - 3)$

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $- x - 3$ .

$y \geq - x - 3$