Graph y>|x+4|-3 y<=-2/3x+1

$y > | x + 4 | - 3$ $y \leq - \frac{2}{3} x + 1$

Graph $y > | x + 4 | - 3$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $| x + 4 | - 3$ .

$y > | x + 4 | - 3$

Graph $y \leq - \frac{2}{3} x + 1$ .

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Simplify each term.

Combine $x$ and $\frac{2}{3}$ .

$y \leq - \frac{x \cdot 2}{3} + 1$

Move $2$ to the left of $x$ .

$y \leq - \frac{2 x}{3} + 1$

Write in $y = m x + b$ form.

Reorder terms.

$y \leq - (\frac{2}{3} x) + 1$

Remove parentheses.

$y \leq - \frac{2}{3} x + 1$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{2}{3}$

$b = 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{2}{3}$

y-intercept: $(0, 1)$

Slope: $- \frac{2}{3}$

y-intercept: $(0, 1)$

Slope: $- \frac{2}{3}$

y-intercept: $(0, 1)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $- \frac{2}{3} x + 1$ .

$y \leq - \frac{2}{3} x + 1$

Plot each graph on the same coordinate system.

$y > | x + 4 | - 3$

$y \leq - \frac{2}{3} x + 1$