Simplify 2 cube root of 27x^3y^6

$2 \sqrt[3]{27 x^{3} y^{6}}$

Step 1

Rewrite $27 x^{3} y^{6}$ as ${(3 x y^{2})}^{3}$ .

$2 \sqrt[3]{{(3 x y^{2})}^{3}}$

Step 2

Pull terms out from under the radical, assuming real numbers.

$2 (3 x y^{2})$

Step 3

Multiply $3$ by $2$ .

$6 x y^{2}$