Simplify/Condense log base 8 of 64+ log base 8 of 8

$\log_{8} (64) + \log_{8} (8)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{8} (64 \cdot 8)$

Multiply $64$ by $8$ .

$\log_{8} (512)$

Logarithm base $8$ of $512$ is $3$ .

$3$