Simplify square root of (2x)/63

$\sqrt{\frac{2 x}{63}}$

Step 1

Rewrite $\frac{2 x}{63}$ as ${(\frac{1}{3})}^{2} \frac{2 x}{7}$ .

Factor the perfect power $1^{2}$ out of $2 x$ .

$\sqrt{\frac{1^{2} (2 x)}{63}}$

Factor the perfect power $3^{2}$ out of $63$ .

$\sqrt{\frac{1^{2} (2 x)}{3^{2} \cdot 7}}$

Rearrange the fraction $\frac{1^{2} (2 x)}{3^{2} \cdot 7}$ .

$\sqrt{{(\frac{1}{3})}^{2} \frac{2 x}{7}}$

Step 2

Pull terms out from under the radical.

$\frac{1}{3} \sqrt{\frac{2 x}{7}}$

Step 3

Rewrite $\sqrt{\frac{2 x}{7}}$ as $\frac{\sqrt{2 x}}{\sqrt{7}}$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x}}{\sqrt{7}}$

Step 4

Multiply $\frac{\sqrt{2 x}}{\sqrt{7}}$ by $\frac{\sqrt{7}}{\sqrt{7}}$ .

$\frac{1}{3} (\frac{\sqrt{2 x}}{\sqrt{7}} \cdot \frac{\sqrt{7}}{\sqrt{7}})$

Step 5

Combine and simplify the denominator.

Multiply $\frac{\sqrt{2 x}}{\sqrt{7}}$ by $\frac{\sqrt{7}}{\sqrt{7}}$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{\sqrt{7} \sqrt{7}}$

Raise $\sqrt{7}$ to the power of $1$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{{\sqrt{7}}^{1} \sqrt{7}}$

Raise $\sqrt{7}$ to the power of $1$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{{\sqrt{7}}^{1} {\sqrt{7}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{{\sqrt{7}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{{\sqrt{7}}^{2}}$

Rewrite ${\sqrt{7}}^{2}$ as $7$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{7}$ as $7^{\frac{1}{2}}$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{{(7^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{7^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{7^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{7^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{7^{1}}$

Evaluate the exponent.

$\frac{1}{3} \cdot \frac{\sqrt{2 x} \sqrt{7}}{7}$

Step 6

Simplify the numerator.

Combine using the product rule for radicals.

$\frac{1}{3} \cdot \frac{\sqrt{2 x \cdot 7}}{7}$

Multiply $7$ by $2$ .

$\frac{1}{3} \cdot \frac{\sqrt{14 x}}{7}$

Step 7

Multiply $\frac{1}{3} \cdot \frac{\sqrt{14 x}}{7}$ .

Multiply $\frac{1}{3}$ by $\frac{\sqrt{14 x}}{7}$ .

$\frac{\sqrt{14 x}}{3 \cdot 7}$

Multiply $3$ by $7$ .

$\frac{\sqrt{14 x}}{21}$

Simplify square root of (2x)/63

Related Questions

Support LCMGCF.com by disabling your adblocker.