Simplify square root of 63x- square root of 28x

$\sqrt{63 x} - \sqrt{28 x}$

Step 1

Simplify each term.

Rewrite $63 x$ as $3^{2} \cdot (7 x)$ .

Factor $9$ out of $63$ .

$\sqrt{9 (7) x} - \sqrt{28 x}$

Rewrite $9$ as $3^{2}$ .

$\sqrt{3^{2} \cdot 7 x} - \sqrt{28 x}$

Add parentheses.

$\sqrt{3^{2} \cdot (7 x)} - \sqrt{28 x}$

$\sqrt{3^{2} \cdot (7 x)} - \sqrt{28 x}$

Pull terms out from under the radical.

$3 \sqrt{7 x} - \sqrt{28 x}$

Rewrite $28 x$ as $2^{2} \cdot (7 x)$ .

Factor $4$ out of $28$ .

$3 \sqrt{7 x} - \sqrt{4 (7) x}$

Rewrite $4$ as $2^{2}$ .

$3 \sqrt{7 x} - \sqrt{2^{2} \cdot 7 x}$

Add parentheses.

$3 \sqrt{7 x} - \sqrt{2^{2} \cdot (7 x)}$

$3 \sqrt{7 x} - \sqrt{2^{2} \cdot (7 x)}$

Pull terms out from under the radical.

$3 \sqrt{7 x} - (2 \sqrt{7 x})$

Multiply $2$ by $- 1$ .

$3 \sqrt{7 x} - 2 \sqrt{7 x}$

$3 \sqrt{7 x} - 2 \sqrt{7 x}$

Step 2

Subtract $2 \sqrt{7 x}$ from $3 \sqrt{7 x}$ .

$\sqrt{7 x}$

Related Questions