Simplify the Radical Expression (4^6)(4^-8)

$(4^{6}) (4^{- 8})$

Step 1

Multiply $4^{6}$ by $4^{- 8}$ by adding the exponents.

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4^{6 - 8}$

Subtract $8$ from $6$ .

$4^{- 2}$

Step 2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{4^{2}}$

Step 3

Raise $4$ to the power of $2$ .

$\frac{1}{16}$