Solve by Addition/Elimination x+y=8 2x=y-5

$x + y = 8$ $2 x = y - 5$

Step 1

Subtract $y$ from both sides of the equation.

$x + y = 8, 2 x - y = - 5$

Step 2

Add the two equations together to eliminate $y$ from the system.

Step 3

Divide each term in $3 x = 3$ by $3$ and simplify.

Divide each term in $3 x = 3$ by $3$ .

$\frac{3 x}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{3}{3}$

Divide $x$ by $1$ .

$x = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$x = 1$

Step 4

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$(1) + y = 8$

Remove parentheses.

$1 + y = 8$

Move all terms not containing $y$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$y = 8 - 1$

Subtract $1$ from $8$ .

$y = 7$

Step 5

The solution to the independent system of equations can be represented as a point.

$(1, 7)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(1, 7)$

Equation Form:

$x = 1, y = 7$

Step 7