Solve by Completing the Square x^2+10x+19=0

$x^{2} + 10 x + 19 = 0$

Step 1

Subtract $19$ from both sides of the equation.

$x^{2} + 10 x = - 19$

Step 2

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(5)}^{2}$

Step 3

Add the term to each side of the equation.

$x^{2} + 10 x + {(5)}^{2} = - 19 + {(5)}^{2}$

Step 4

Simplify the equation.

Simplify the left side.

Raise $5$ to the power of $2$ .

$x^{2} + 10 x + 25 = - 19 + {(5)}^{2}$

Simplify the right side.

Simplify $- 19 + {(5)}^{2}$ .

Raise $5$ to the power of $2$ .

$x^{2} + 10 x + 25 = - 19 + 25$

Add $- 19$ and $25$ .

$x^{2} + 10 x + 25 = 6$

Step 5

Factor the perfect trinomial square into ${(x + 5)}^{2}$ .

${(x + 5)}^{2} = 6$

Step 6

Solve the equation for $x$ .

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 5 = \pm \sqrt{6}$

Subtract $5$ from both sides of the equation.

$x = \pm \sqrt{6} - 5$

Step 7

The result can be shown in multiple forms.

Exact Form:

$x = \pm \sqrt{6} - 5$

Decimal Form:

$x = - 2.55051025 \dots, - 7.44948974 \dots$