Solve by Factoring 4(y-1)-1=2(2y-3)

$4 (y - 1) - 1 = 2 (2 y - 3)$

Step 1

Subtract $2 (2 y - 3)$ from both sides of the equation.

$4 (y - 1) - 1 - 2 (2 y - 3) = 0$

Step 2

Simplify $4 (y - 1) - 1 - 2 (2 y - 3)$ .

Simplify each term.

Apply the distributive property.

$4 y + 4 \cdot - 1 - 1 - 2 (2 y - 3) = 0$

Multiply $4$ by $- 1$ .

$4 y - 4 - 1 - 2 (2 y - 3) = 0$

Apply the distributive property.

$4 y - 4 - 1 - 2 (2 y) - 2 \cdot - 3 = 0$

Multiply $2$ by $- 2$ .

$4 y - 4 - 1 - 4 y - 2 \cdot - 3 = 0$

Multiply $- 2$ by $- 3$ .

$4 y - 4 - 1 - 4 y + 6 = 0$

Combine the opposite terms in $4 y - 4 - 1 - 4 y + 6$ .

Subtract $4 y$ from $4 y$ .

$0 - 4 - 1 + 6 = 0$

Subtract $4$ from $0$ .

$- 4 - 1 + 6 = 0$

Subtract $1$ from $- 4$ .

$- 5 + 6 = 0$

Add $- 5$ and $6$ .

$1 = 0$

Step 3

Since $1 \neq 0$ , there are no solutions.

No solution