Solve for x 5(x+1)<=5x+3

$5 (x + 1) \leq 5 x + 3$

Step 1

Simplify $5 (x + 1)$ .

Rewrite.

$0 + 0 + 5 (x + 1) \leq 5 x + 3$

Simplify by adding zeros.

$5 (x + 1) \leq 5 x + 3$

Apply the distributive property.

$5 x + 5 \cdot 1 \leq 5 x + 3$

Multiply $5$ by $1$ .

$5 x + 5 \leq 5 x + 3$

Step 2

Move all terms containing $x$ to the left side of the inequality.

Subtract $5 x$ from both sides of the inequality.

$5 x + 5 - 5 x \leq 3$

Combine the opposite terms in $5 x + 5 - 5 x$ .

Subtract $5 x$ from $5 x$ .

$0 + 5 \leq 3$

Add $0$ and $5$ .

$5 \leq 3$

Step 3

Since $5 \neq 3$ , there are no solutions.

No solution