Solve by Factoring 5x^2+20x=0

$5 x^{2} + 20 x = 0$

Step 1

Factor $5 x$ out of $5 x^{2} + 20 x$ .

Factor $5 x$ out of $5 x^{2}$ .

$5 x (x) + 20 x = 0$

Factor $5 x$ out of $20 x$ .

$5 x (x) + 5 x (4) = 0$

Factor $5 x$ out of $5 x (x) + 5 x (4)$ .

$5 x (x + 4) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x + 4 = 0$

Step 3

Set $x$ equal to $0$ .

$x = 0$

Step 4

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 5

The final solution is all the values that make $5 x (x + 4) = 0$ true.

$x = 0, - 4$