Solve by Graphing 3x-y=8 12x-4y=8

$3 x - y = 8$ $12 x - 4 y = 8$

Step 1

Subtract $3 x$ from both sides of the equation.

$- y = 8 - 3 x$

$12 x - 4 y = 8$

Step 2

Divide each term in $- y = 8 - 3 x$ by $- 1$ and simplify.

Divide each term in $- y = 8 - 3 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{8}{- 1} + \frac{- 3 x}{- 1}$

$12 x - 4 y = 8$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{8}{- 1} + \frac{- 3 x}{- 1}$

$12 x - 4 y = 8$

Divide $y$ by $1$ .

$y = \frac{8}{- 1} + \frac{- 3 x}{- 1}$

$12 x - 4 y = 8$

$y = \frac{8}{- 1} + \frac{- 3 x}{- 1}$

$12 x - 4 y = 8$

Simplify the right side.

Simplify each term.

Divide $8$ by $- 1$ .

$y = - 8 + \frac{- 3 x}{- 1}$

$12 x - 4 y = 8$

Move the negative one from the denominator of $\frac{- 3 x}{- 1}$ .

$y = - 8 - 1 \cdot (- 3 x)$

$12 x - 4 y = 8$

Rewrite $- 1 \cdot (- 3 x)$ as $- (- 3 x)$ .

$y = - 8 - (- 3 x)$

$12 x - 4 y = 8$

Multiply $- 3$ by $- 1$ .

$y = - 8 + 3 x$

$12 x - 4 y = 8$

$y = - 8 + 3 x$

$12 x - 4 y = 8$

$y = - 8 + 3 x$

$12 x - 4 y = 8$

$y = - 8 + 3 x$

$12 x - 4 y = 8$

Step 3

Subtract $12 x$ from both sides of the equation.

$- 4 y = 8 - 12 x$

$y = - 8 + 3 x$

Step 4

Divide each term in $- 4 y = 8 - 12 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 8 - 12 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{8}{- 4} + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{8}{- 4} + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

Divide $y$ by $1$ .

$y = \frac{8}{- 4} + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

$y = \frac{8}{- 4} + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

$y = \frac{8}{- 4} + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

Simplify the right side.

Simplify each term.

Divide $8$ by $- 4$ .

$y = - 2 + \frac{- 12 x}{- 4}$

$y = - 8 + 3 x$

Cancel the common factor of $- 12$ and $- 4$ .

Factor $- 4$ out of $- 12 x$ .

$y = - 2 + \frac{- 4 (3 x)}{- 4}$

$y = - 8 + 3 x$

Cancel the common factors.

Factor $- 4$ out of $- 4$ .

$y = - 2 + \frac{- 4 (3 x)}{- 4 \cdot 1}$

$y = - 8 + 3 x$

Cancel the common factor.

$y = - 2 + \frac{- 4 (3 x)}{- 4 \cdot 1}$

$y = - 8 + 3 x$

Rewrite the expression.

$y = - 2 + \frac{3 x}{1}$

$y = - 8 + 3 x$

Divide $3 x$ by $1$ .

$y = - 2 + 3 x$

$y = - 8 + 3 x$

$y = - 2 + 3 x$

$y = - 8 + 3 x$

$y = - 2 + 3 x$

$y = - 8 + 3 x$

$y = - 2 + 3 x$

$y = - 8 + 3 x$

$y = - 2 + 3 x$

$y = - 8 + 3 x$

$y = - 2 + 3 x$

$y = - 8 + 3 x$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

No solution

Step 6

Solve by Graphing 3x-y=8 12x-4y=8

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