Solve by Graphing x+4y=8 y=3/4x+6

$x + 4 y = 8$ $y = \frac{3}{4} x + 6$

Subtract $x$ from both sides of the equation.

$4 y = 8 - x$

$y = \frac{3}{4} x + 6$

Divide each term in $4 y = 8 - x$ by $4$ and simplify.

Divide each term in $4 y = 8 - x$ by $4$ .

$\frac{4 y}{4} = \frac{8}{4} + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{8}{4} + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

Divide $y$ by $1$ .

$y = \frac{8}{4} + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

$y = \frac{8}{4} + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

$y = \frac{8}{4} + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

Simplify the right side.

Simplify each term.

Divide $8$ by $4$ .

$y = 2 + \frac{- x}{4}$

$y = \frac{3}{4} x + 6$

Move the negative in front of the fraction.

$y = 2 - \frac{x}{4}$

$y = \frac{3}{4} x + 6$

$y = 2 - \frac{x}{4}$

$y = \frac{3}{4} x + 6$

$y = 2 - \frac{x}{4}$

$y = \frac{3}{4} x + 6$

$y = 2 - \frac{x}{4}$

$y = \frac{3}{4} x + 6$

Combine $\frac{3}{4}$ and $x$ .

$y = \frac{3 x}{4} + 6$

$y = 2 - \frac{x}{4}$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 4, 3)$