Solve by Substitution 11x-7y=-14 and x-2y=-4

$11 x - 7 y = - 14$ and $x - 2 y = - 4$

Add $2 y$ to both sides of the equation.

$x = - 4 + 2 y$

$11 x - 7 y = - 14$

Replace all occurrences of $x$ with $- 4 + 2 y$ in each equation.

Replace all occurrences of $x$ in $11 x - 7 y = - 14$ with $- 4 + 2 y$ .

$11 (- 4 + 2 y) - 7 y = - 14$

$x = - 4 + 2 y$

Simplify the left side.

Simplify $11 (- 4 + 2 y) - 7 y$ .

Simplify each term.

Apply the distributive property.

$11 \cdot - 4 + 11 (2 y) - 7 y = - 14$

$x = - 4 + 2 y$

Multiply $11$ by $- 4$ .

$- 44 + 11 (2 y) - 7 y = - 14$

$x = - 4 + 2 y$

Multiply $2$ by $11$ .

$- 44 + 22 y - 7 y = - 14$

$x = - 4 + 2 y$

$- 44 + 22 y - 7 y = - 14$

$x = - 4 + 2 y$

Subtract $7 y$ from $22 y$ .

$- 44 + 15 y = - 14$

$x = - 4 + 2 y$

$- 44 + 15 y = - 14$

$x = - 4 + 2 y$

$- 44 + 15 y = - 14$

$x = - 4 + 2 y$

$- 44 + 15 y = - 14$

$x = - 4 + 2 y$

Solve for $y$ in $- 44 + 15 y = - 14$ .

Move all terms not containing $y$ to the right side of the equation.

Add $44$ to both sides of the equation.

$15 y = - 14 + 44$

$x = - 4 + 2 y$

Add $- 14$ and $44$ .

$15 y = 30$

$x = - 4 + 2 y$

$15 y = 30$

$x = - 4 + 2 y$

Divide each term in $15 y = 30$ by $15$ and simplify.

Divide each term in $15 y = 30$ by $15$ .

$\frac{15 y}{15} = \frac{30}{15}$

$x = - 4 + 2 y$

Simplify the left side.

Cancel the common factor of $15$ .

Cancel the common factor.

$\frac{15 y}{15} = \frac{30}{15}$

$x = - 4 + 2 y$

Divide $y$ by $1$ .

$y = \frac{30}{15}$

$x = - 4 + 2 y$

$y = \frac{30}{15}$

$x = - 4 + 2 y$

$y = \frac{30}{15}$

$x = - 4 + 2 y$

Simplify the right side.

Divide $30$ by $15$ .

$y = 2$

$x = - 4 + 2 y$

$y = 2$

$x = - 4 + 2 y$

$y = 2$

$x = - 4 + 2 y$

$y = 2$

$x = - 4 + 2 y$

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = - 4 + 2 y$ with $2$ .

$x = - 4 + 2 (2)$

$y = 2$

Simplify the right side.

Simplify $- 4 + 2 (2)$ .

Multiply $2$ by $2$ .

$x = - 4 + 4$

$y = 2$

Add $- 4$ and $4$ .

$x = 0$

$y = 2$

$x = 0$

$y = 2$

$x = 0$

$y = 2$

$x = 0$

$y = 2$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, 2)$

The result can be shown in multiple forms.

Point Form:

$(0, 2)$

Equation Form:

$x = 0, y = 2$

Solve by Substitution 11x-7y=-14 and x-2y=-4

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